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laiz [17]
3 years ago
11

7. A 600g brick weighs 6N in the air. If the brick displaces 2N of water when it is

Physics
1 answer:
Oxana [17]3 years ago
6 0
The answer to this would be 12N
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According to Newton's third law, if you push on a wall, the wall ?
Lady bird [3.3K]

The wall will push back, in exactly the opposite direction, and with
exactly the same size force.

That's why the net force on the palm of your hand is zero, and that
in turn is the reason that your hand doesn't accelerate.

If you keep increasing the strength of your push, then eventually you
exceed the force that the wall is capable of delivering.  Then the wall
crumbles and falls, your hand accelerates in the direction you're pushing,
and the crowd goes wild !


3 0
3 years ago
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What are the units of impulse
attashe74 [19]

Answer:

Newton Second

Explanation:

The SI unit of impulse in Newton Second (N.s)

3 0
3 years ago
An industrial overhead door has a chain and sprocket system designed to reduce the force needed by an operator to open and close
mylen [45]
GR/1=nout/nin = 48/22=2.18/1
4 0
4 years ago
PLS HELP!! WILL GIVE BRAINIEIST!!!!!
8_murik_8 [283]
1, 2 and 4 apply. im not sure that 2 ALWAYS applies though.
4 0
3 years ago
A 2.0 kg otter starts from rest at the top of a muddy incline 85 cm long and slides down to the bottom in 0.50 s. What net force
Julli [10]

Answer:

The net force acting on the otter along the incline is 13.96 N.

Explanation:

It is given that,

Mass of the otter, m = 2 kg

Distance covered by otter, d = 85 cm = 0.85 m

It takes 0.5 seconds.

We need to find the net force acts on the otter along the incline. If a is the acceleration of the otter. It can be calculated using second equation of motion as :

d=ut+\dfrac{1}{2}at^2

Here, u = 0 (at rest)

d=\dfrac{1}{2}at^2

a=\dfrac{2d}{t^2}

a=\dfrac{2\times 0.85}{0.5^2}

a=6.8\ m/s^2

The net force acting on the otter along the incline is given by :

F = ma

F=2\ kg\times 6.8\ m/s^2

F = 13.6 N

So, the net force acting on the otter along the incline is 13.96 N. Hence, this is the required solution.

5 0
4 years ago
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