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dsp73
3 years ago
6

A 1425 kg truck driving at 13.0 m/s collides elastically with a stationary 1175 kg car. If the car is traveling 14.25 m/s just a

fter the collision, what is the velocity of the truck immediately after the collision
Physics
1 answer:
TEA [102]3 years ago
4 0

Answer:

1.25 m/s

Explanation:

m1v1+m2v2=m1v1f+m2v2f

(1425*13)+(1175*0)=(1425*v1f)+(1175*14.25)

18525+0=1425(v1f)+16743.75

1781.25=1425(v1f)

v1f=1.25 m/s

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Describe a perfect day
kvv77 [185]

Answer:

A bright and sunny day not worrying about work or school no family drama just a day you can relax and be yourself surrounded by the people you love.

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Explanation:

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3 years ago
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Is space expanding within clusters of galaxies? why or why not?
GarryVolchara [31]

No, since their gravity is powerful enough to keep them together even while the universe expands as a whole. Space is not expanding within clusters of galaxies.

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A galaxy is a massive clump of gas, dust, and billions of stars and their solar systems bound together by gravity.

No, since their gravity is powerful enough to keep them together even while the universe expands as an entire.

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6 0
2 years ago
A 0.350-m-long cylindrical capacitor consists of a solid conducting core with a radius of 1.20 mm and an outer hollow conducting
Brut [27]

Answer: a. 6.52*EXP{-10}C/m. b. 2.28*EXP{-10}C. c. 38picoFarad.

d. 6.84*EXP{-10}joules

Explanation: We first calculate for the capacitance first. For a concetric cylinder with two radius R1 and R2 the capacitance C is given as

C= {2*pi*permitivity of

freespace*lenght}/In(R2/R1) from the given Question R2 is 2mm and R1 is 1.2mm, lenght is 0.35meter, permitivity of free space is 8.85*EXP {-12} and pi is 3.142.

Therefore Capacitance would be,

C = 2*3.142*8.85*EXP

{-12}*0.35/In(2/1.2)

C = 3.8*EXP {-11} Farad which is also

38*EXP {-12} Farad or 38picoFarad.

Next, we solve for our total charge Q. Charge, capacitance and voltage are related by

Q = C*V = 38*EXP {-12}*6

=2.28*EXP {-10} Coulombs

Next, we obtian charge per unit lenght, which is

Q/L = 2.28*EXP {-10}/0.35

= 6.52*EXP {-10} Coulombs/meter

Next, we obtain the energy stored in the capacitor from

Energy stored = 1/2*(C*V²)

=1/2*38*EXP {-12}*6²

=6.84*EXP {-10} Joules

Note: EXP means 10^

4 0
3 years ago
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lilavasa [31]

Answer: ok

Explanation:

5 0
3 years ago
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A bicycle generator rotates at 154 rads/s, producing an 16.5 V peak emf. It has a 1.00 by 3.00 cm rectangular coil in a 0.68 T f
WITCHER [35]

Answer:

525.2

Explanation:

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By use of law of electromagnetic induction

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16.5 = N x 0.68 x 3 x 10^-4 x 154

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3 years ago
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