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adell [148]
3 years ago
13

The circuit below shows some of the circuitry in a small toy robot. When the circuit is on the robot moves its arms, the motor,

and blink the light on its head, the lightbulb.
A. How much current Is in the circuit when these things are happening? Hint defined the total resistance of the circuit add the two resistances together.


B. What is the voltage between point P and the battery?

Physics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

A. 0.25 A

B. 4.5 V

Explanation:

A. The total resistance of resistances in series is:

R = R₁ + R₂

R = 18 Ω + 18 Ω

R = 36 Ω

Ohm's law:

V = IR

9 V = I (36 Ω)

I = 0.25 A

B. The voltage across the bulb (between P and the battery) can be found with Ohm's law.

V = IR

V = (0.25 A) (18 Ω)

V = 4.5 V

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Neko [114]
The height of the ball when lifted is given by 7sin(25)=2.96
the gravitational energy is mgh, the kinetic is (1/2)mv².  We can set these equal since the pendulum doesn't lose much energy
mgh = (1/2)mv²
we can divide by m (since we don't have it anyways)
gh = v²/2
v=√(gh/2) = √(9.81*2.96/2)=3.8m/s.
Not exactly one of your choices, but the right one none the less
6 0
3 years ago
A 70 watt light bulb is run by a 120 v circuit. how many amps does it use
Marizza181 [45]
Current = Power/Voltage. 70W/120v= 0.583 Amps.
6 0
4 years ago
In order to determine the coefficients of friction between rubber and various surfaces, a student uses a rubber eraser and an in
Strike441 [17]

Answer:

μs = 0.75

μk = 0.58

Explanation:

From a force diagram:

m*g*sin \theta - Ff=m*a     (1)

N-m*g*cos \theta = 0         (2)

When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):

m*g*sin \theta - \mu*m*g*cos \theta=0   Solving for μs:

\mu=tan \theta

μs = tan 36.7° = 0.75

When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:

μk = tan 30.1° = 0.58

8 0
4 years ago
a solid object is found to weigh 4.784.78n in air. when it is weighed while fully immersed in water, its apparent weight is 2.48
ololo11 [35]

A solid object is found to weigh 4.784.78n in air. when it is weighed while fully immersed in water, its apparent weight is 2.482.48n. 983 is the density of the object.

The substance's density is defined as its mass per unit of volume (volumetric mass density or specific mass). Although the Latin letter D may also be used, the symbol for density that is most usually used is (the lower case Greek letter rho). where V is the volume, is the density, and m is the mass. Weight per unit volume is a common informal definition of density, however this is incorrect scientifically; the actual term is specific weight. The US oil and gas industry serves as one illustration of this. A pure substance's mass concentration in numbers is equal to its density. To make density comparisons between different systems of units easier, it is occasionally replaced by the dimensionless quantity "relative density" or "specific gravity," which is the ratio of the density of the material to that of a standard material, usually water. If a substance's relative density to water is less than one, it will float in it. Temperature and pressure have an impact on a substance's density. This variation is frequently not very noticeable for solids and liquids, but it is very noticeable for gases. As pressure is applied, an object's density rises, which reduces the object's volume. With a few rare exceptions, as temperature increases, a substance's density decreases as its volume grows.

To know more about density please refer: brainly.com/question/15164682

#SPJ4

3 0
1 year ago
BRAINLIEST AND MAY DOUBLE POINTS!!!
raketka [301]

Given that:

 Energy of bulb  (Work ) = 30 J,

 Time (t) = 3 sec

The power consumption =  ?

 We know that, Power can be defined as rate of doing work

              Power (P) = Work(Energy supplied) ÷ time

                               = 30 ÷ 3

                              = 10 Watts

<em> The power consumption is 10 W.</em>


3 0
3 years ago
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