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Anna11 [10]
3 years ago
14

Help me ASAP PLEASE thanks Please show work Random answers will be moderated

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0
He's wrong. Both equations refer to the same line, that's why he saw only one line. The solution to the system is the set of real numbers.
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I need to find side x in its simplest radical form using the special right triangles method
crimeas [40]

Answer:

\sqrt{6}

Explanation:

From the given diagram,

Hypotenuse sde = x

Opposite side = \sqrt{3}

Using the SOH CAH TOA identity

Sintheta = opposite/hypotenuse

Sin 45 = \sqrt{3}/x

x = \sqrt{3}/sin45

\begin{gathered} x\text{ =}\frac{\sqrt[]{3}}{\sin 45} \\ x\text{ = }\frac{\sqrt[]{3}}{\frac{1}{\sqrt[]{2}}} \\ x\text{ = }\sqrt[]{3^{}}\cdot\sqrt[]{2} \\ x\text{ =}\sqrt[]{6} \end{gathered}

Hence the value of x is \sqrt{6}

5 0
1 year ago
Q # 13. please help to solve this
True [87]
To solve this problem you must apply the fomrula for calculate the area of a cylinder, which is shown below:
 A=2πrh+2πr^2
 Where r is the radius and h is the height of the cylinder
 You have that r=15.1 inches and h=12.8 inches, then:
 A=2πrh+2r^2
 A=2π(15.1 in)(12.8 in)+2π(15.1 in)^2 
 A=2647 in^2
 The answer is 2647 in^2
3 0
3 years ago
Someone help me find out what is the area
melamori03 [73]

Answer:

SA = 31.714 km²

Step-by-step explanation:

SA = πr² + πrl

SA = 3.14(1)² + 3.14(1)(9.1)

SA = 3.14 + 28.574

SA = 31.714 km²

3 0
2 years ago
These map tests give me anxiety or however you spell it
Vesnalui [34]

Answer:

Im sorry i dont know what im supposed to be answering

step-by-step explanation:

5 0
3 years ago
Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

\implies \sf{2tan^2x -  5tanx + 2tanx - 5 = 0}

\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}

\implies \sf{(tanx + 1)(2tanx - 5) = 0}

\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

8 0
2 years ago
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