You have to take the percentage of the original price and subtract it to find the reduced price
To solve this question, we just need to insert 12 into the m position of each question and see if the equation holds true.
a. 4m = 40
4(12) = 40
48 = 40
48 obviously does not equal 40, so it is not choice A.
b. m + 20 = 42
12 + 20 = 42
32 = 42
Again, 32 isn't the same as 42, so not choice B either.
c. 4m = 48
4(12) = 48
48 = 48
It looks like this one is true, but let's solve D also just to make sure.
d. m - 4 = 9
12 - 4 = 9
8 = 9
This is false, since 8 does not equal 9.
Therefore, choice C (4m = 48) is the correct answer.
Hope that helped! =)
Answer: First half was 24 minutes
Step-by-step explanation:
Let the time taken to finish the second half be y.
Since the student used 2/3 of the second half time to finish the first half, first half = 2/3 × y = 2y/3
The entire exam is an hour which equals 60 minutes
First half + Second half = 60minutes
Note that first half is denoted as 2y/3 and second half is denoted by y.
2y/3 + y = 60
5y/3 = 60
Cross multiply
5y = 60 × 3
5y = 180
y = 180/5
y = 36
Second half took 36 minutes
Since first half is 2y/3, it will be:
(2×36) / 3
= 72/3
= 24minutes
First half took 24 minutes.
-6z = 72
Divide both sides by -6
-6z = 72
/-6 /-6
z = -12
The answer is b so good luck and i hope that helps
