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crimeas [40]
3 years ago
8

Using only the information derived in questions 2,3, and 4 which theorem or postulate can be used to prove abe=cde?

Mathematics
2 answers:
Tasya [4]3 years ago
8 0

using only the information derived in question 2, 3, and 4, which theorem

D. AAS










ycow [4]3 years ago
4 0

Congruence In Overlapping Triangles - Quickcheck (Connexus)

1.  <PQT

2. AB = CD

3. Vertical angles are congruent

4. CDE = ABE

5. AAS

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HELP PLS QUICK MIGHT GIVE BRAINLIST ONLY IF 2 PEOPLE ANSWER!
Afina-wow [57]

Answer:

area = 10 squares units

if points changes

5 0
2 years ago
A class at Middlebury school collected date on the types of movies students prefer. Complete each statement using the table.
likoan [24]

Based on the information of the table, you have:

1. The ratio is 105/150. By simplifying you get for the ratio 7/10.

2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:

165/420 = 11/28

3. The fraction of seventh graders students that prefer action movies is:

75/180 = 5/12

4. The percent of student that prefer comedy is:

105 + 150 = 255 total student that prefer comedy

420 total number of students

the fraction is:

(x/100)420 = 255

solve for x:

x = 255(100/420)

x = 60.71

the percent of students is 60.71%

5. The percent of eighth graders student who prefer action moveis is:

(x/100)240 = 90

x = 90(100/240)

x = 37.5

the percent of students is 37.5%

6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:

(x/100)180 = 75

x = 75(100/180)

x = 41.66

the percent of student is 41.66%

then, seventh grade has the greatest percent of student that prefer action movies.

4 0
10 months ago
22+6[(14-5)÷3(17-14)]
mina [271]

The simplification of the expression is 28. The mistake in your calculation occurred in step 3.

<h3>What is the process involved in simplifying expression involving brackets?</h3>

TO simplify expressions involving brackets, we use a common method called BODMAS (Brackets, Of, Division, Multiplication, Addition, and Subtraction).

This means that we will first solve the expression in brackets first, followed by division, multiplication, addition, and subtraction as the case may be.

Now, from the given information, we have:
= 22+6[(14-5)÷3(17-14)]

solving parameters in the bracket first, we have:
= 22 + 6[(9) ÷3(3)]

= 22 + 6[(9) ÷9]          

  • The above step is where you missed it from your calculation, you must first open all brackets within brackets before solving them.

= 22 + 6[(9) ÷9]    

= 22 + 6[ 1]

= 22 + 6

= 28

Learn more about simplifying expressions here:

brainly.com/question/723406

#SPJ1

8 0
2 years ago
Find the area of the circle if the square has an area of 900 in2. give your answer in terms of.
svp [43]
First find the square root of 900 to get one side of the square, which is 30 inches.
Formula for area of a circle: pi times the radius(squared)
The radius is 15 because one side of the square equals the diameter of the circle. 15 squared is 225.
3.14x225=<u>706.5 inches squared

</u>I hope this helps, because I did not have a diagram of the problem, but this should be the answer if the circle is inscribed in the square.<u>
</u>
6 0
3 years ago
Find a equation of a line that is perpendicular to y=-4x+3 and passes through the point (4,-1).
Marina86 [1]

Given:

The given equation is:

y=-4x+3

A line is perpendicular to the given line and passes through the point (4,-1).

To find:

The equation of required line.

Solution:

The slope intercept form of a line is:

y=mx+b

Where, m is slope and b is y-intercept.

We have,

y=-4x+3

Here, the slope of the line is -4 and the y-intercept is 3.

Let the slope of required line be m.

We know that the product of slopes of two perpendicular lines is -1. So,

m\times (-4)=-1

m=\dfrac{-1}{-4}

m=\dfrac{1}{4}

The slope of required line is m=\dfrac{1}{4} and it passes through the point (4,-1). So, the equation of the line is:

y-(-1)=\dfrac{1}{4}(x-4)

y+1=\dfrac{1}{4}(x)-\dfrac{4}{4}

y=\dfrac{1}{4}x-1-1

y=\dfrac{1}{4}x-2

Therefore, the equation of the required line is y=\dfrac{1}{4}x-2.

5 0
2 years ago
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