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katovenus [111]
2 years ago
9

How do we add two irrational numbers?

Mathematics
1 answer:
quester [9]2 years ago
5 0
Let x > 0 be irrational<span>, then 1 − x is also </span>irrational<span>, and the </span>sum<span> of these </span>two<span>irrationals is one, which is </span>rational<span>. The question is much harder if you ask under what circumstances </span>adding two irrational numbers<span> produces an </span>irrational<span>. It is near impossible if you then substitute transcendental for </span>irrational<span>! Hope it helps

</span>
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The graph shows the price, in dollars, of different numbers of muffins at David's store. The table shows the price, in dollars,
mash [69]
It should be $4 sorry if it is wrongbut i pretty sure that is he answer

8 0
3 years ago
Read 2 more answers
What’s the probability of getting each card out of a deck?
VMariaS [17]

Answer:

a. 1/13

b. 1/52

c. 2/13

d. 1/2

e. 15/26

f. 17/52

g. 1/2

Step-by-step explanation:

a. In a deck of cards, there are 4 suits and each of them has a 7. Therefore, the probability of drawing a 7 is:

P(7) = 4/52 = 1/13

b. There is only one 6 of clubs, therefore, the probability of drawing a 6 of clubs is:

P(6 of clubs) = 1/52

c. There 4 fives (one for each suit) and 4 queens in a deck of cards. Therefore, the probability of drawing a five or a queen​​​​​​​​​​​ is:

P(5 or Q) = P(5) + P(Q)

= 4/52 + 4/52

= 1/13 + 1/13

P(5 or Q) = 2/13

d. There are 2 suits that are black. Each suit has 13 cards. Therefore, there are 26 black cards. The probability of drawing a black card is:

P(B) = 26/52 = 1/2

e. There are 2 suits that are red. Each suit has 13 cards. Therefore, there are 26 red cards. There are 4 jacks. Therefore:

P(R or J) = P(R) + P(J)

= 26/52 + 4/52

= 30/52

P(R or J) = 15/26

f. There are 13 cards in clubs suit and there are 4 aces, therefore:

P(C or A) = P(C) + P(A)

= 13/52 + 4/52

P(C or A) = 17/52

g. There are 13 cards in the diamonds suit and there are 13 in the spades suit, therefore:

P(D or S) = P(D) + P(S)

= 13/52 + 13/52

= 26/52

P(D or S) = 1/2

6 0
2 years ago
A jeweler wants to minimize business costs and has found that the average cost in dollars per necklace is given by C(x)=0.5x^2-7
Vika [28.1K]

Answer:

The maximum cost is 41 dollars per necklace.

Step-by-step explanation:

The average cost in dollars/necklace is given by :

C(x)=0.5x^2-7x+65.5  .....(1)

Where

x is the number of necklaces that are created

To maximize the cost, find the value of x by putting dC/dx = 0

\dfrac{d}{dx}(0.5x^2-7x+65.5)=0\\\\x-7=0\\\\x=7

Now put the value of x = 7 in equation (1).

C(x)=0.5(7)^2-7(7)+65.5\\\\=41\ \text{dollars per necklace}

Hence, the maximum cost is 41 dollars per necklace.

8 0
2 years ago
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Masja [62]
Let the number of weeks to have same amount = x Then:-

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answer is 50 weeks
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2 years ago
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PIT_PIT [208]

Answer:

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2. Formula: b * h ÷ 2

5 * 8 = 40 ÷ 2 = 20 ft^2

I could only help on two. Hope it helps though! =)

5 0
2 years ago
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