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3 years ago

4) This results when you flip the numerator and denominator of a fraction.

Mathematics

1 answer:

ryzh [129]3 years ago

4 0

Answer:

I think its the inverse

Step-by-step explanation:

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6(3u+4) please help I am in a classwork

frozen [14]

Answer:

18u+24

Step-by-step explanation:hope this helps xxx

7 0

2 years ago

Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .

6 0

3 years ago

I need help pleaseeeee Prove that: 12^13–12^12+12^11 is divisible by 7 and 19. BTW in format ______*7*19 :D

iragen [17]

Each term has a common divisor of $12^{11}$ :

$12^{13}-12^{12}+12^{11}=12^{11}(12^2-12+1)=12^{11}\cdot133$

133 = 7*19, so the number in the blanks is $12^{11}$ .

3 0

3 years ago

Describe the transformation done to y = 1/x to get y = 1/4x -12?

BabaBlast [244]

The transformation is done to y=1/x to get y=1/4x-12. We defined a turning point in the equation which will indicate the point in the graph.

We changed the form from y=x to y=x+c. In this case, we use 1/2 for the and constant C value which is -12.

3 0

3 years ago

Someone please help me?

kow [346]

So hmmm recall the "inscribed angle theorem", notice the first picture

thus, check the second picture, recall, a flat line line AOD is 180° wide

8 0

2 years ago