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Ilia_Sergeevich [38]
3 years ago
11

A Turing machine with doubly infinite tape is similar to an ordinary Turing machine, but its tape is infinite to the left as wella

s to the right The tape is initially filled with blanks except for the portion that contains the input. Computation is definedas usual except that the head never encounters an end to the tape as it moves leftward. Show that this type of Turingmachine recognizes the class of Turing- recognizable languages.
Mathematics
1 answer:
atroni [7]3 years ago
8 0

Answer:

Use multitape Turing machine to simulate doubly infinite one

Explanation:

It is obvious that Turing machine with doubly infinite tape can simulate ordinary TM. For the other direction, note that 2-tape Turing machine is essentially itself a Turing machine with doubly (double) infinite tape. When it reaches the left-hand side end of first tape, it switches to the second one, and vice versa.

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Consider the rational number, −0.4. Is the number greater than −2 and 1/3 but less than 4/5 ?
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Answer:

No

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Since the rational number -0.4 is a negative, it cannot have a greater value than 1/3 since it is a positive.

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Please help .........​
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Answer:

+10

Step-by-step explanation:

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2 years ago
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Which system of equations can be used to find the roots of the equation 12 x 3-5x=2 x 2+x+6
kirill [66]

Answer:

Option (a) is correct.

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y=12x^3-5x\\\\ y=2x^2+x+6

Step-by-step explanation:

Given : Equation  12x^3-5x=2x^2+x+6

We have to construct a  system of equations that  can be used to find the roots of the equation 12x^3-5x=2x^2+x+6

Consider the given equation 12x^3-5x=2x^2+x+6

To construct a system of equation put both sides of the given equation equal to a same variable.

Let the variable be "y", Then the equation 12x^3-5x=2x^2+x+6

becomes,

12x^3-5x=y=2x^2+x+6

Thus, The system of equation becomes

y=12x^3-5x\\\\ y=2x^2+x+6

Option (a) is correct.

   

8 0
3 years ago
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