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Ilia_Sergeevich [38]
4 years ago
11

A Turing machine with doubly infinite tape is similar to an ordinary Turing machine, but its tape is infinite to the left as wella

s to the right The tape is initially filled with blanks except for the portion that contains the input. Computation is definedas usual except that the head never encounters an end to the tape as it moves leftward. Show that this type of Turingmachine recognizes the class of Turing- recognizable languages.
Mathematics
1 answer:
atroni [7]4 years ago
8 0

Answer:

Use multitape Turing machine to simulate doubly infinite one

Explanation:

It is obvious that Turing machine with doubly infinite tape can simulate ordinary TM. For the other direction, note that 2-tape Turing machine is essentially itself a Turing machine with doubly (double) infinite tape. When it reaches the left-hand side end of first tape, it switches to the second one, and vice versa.

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In the figure shown, what is the measure of angle x?
mojhsa [17]
Angles in a triangle must add up to 180, so the missing angle inside the triangle is 180 - (70 + 40), which is 70.

Angles on a straight line (i.e. the line BD) must add up to 180, and because we know part of that angle is 70, x must be 180 - 70, which is 110.

Hence, x is 110 degrees.
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A math book costs $9 and a science book costs $7. If Steve spends all his money in the science books, he still has $6 left. Howe
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A. 7 books each
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2 years ago
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Which expressions are equivalent to (7^-2)*(7^6)
Ierofanga [76]

Answer:

D

Step-by-step explanation:

(7^-2)*(7^6)=7^-2+6

......since the base 7 is the same, when u multiply them, you should add the exponents and keep 7 as it is. That will be 7^4, which in equivalent to ans D(7^2)^2.

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3 years ago
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The area of this square
ANEK [815]

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7 0
3 years ago
For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in
Rainbow [258]

Answer:

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

x₁ - 5x₂ + x₄ = 5

Matrix form

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}  \begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}

Generally the echelon reduction is mathematically applied as

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -2 times the 1st row to the 2nd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}

Multiply the 2nd row by -1/8  

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -1 times the 2nd row to the 3rd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}

Multiply the 3rd row by -8/41

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

\begin{Vmatrix}1 & 3 & 0&49/41&165/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -3 times the 2nd row to the 1st row

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

3 0
3 years ago
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