Answer:
| x-3| >1:
x>4 or x<2
| 2x+5 | >0.5
:
x > −2.25 or x < −2.75
| 0.2x+3.5 | > 1.7:
x > −9 or x < −26
| x+3 | <1:
x < −2 and x > −4
| 2x+5 | <0.5
x < −2.25 and x > −2.75
| 0.2x+6 | <0.15
x < −29.25 and x > −30.75
| x+5 | >-1
x > −6 or x < −4
| 2x+3 | <-1
No solutions.
| 0.7x +5 | >6.7
x>2.428571 or x<−16.714286
Visualize one train going north and the other going south. To determine their distance apart, we could add the distance one train travels north to the distance that the other train travels south.
Thus, |62 kph * t| + |68 kph * t] = 455 km (Seems that you may be mixing km with miles; can't do that; choose one or the other.)
Then
455 km
------------------------ = t = 3.5 hours
(62 kph + 68 kph)
Use Pythagoras 6 squared =36-(4x4) =20 square root of 20 then times that by two
Answer:
D
Step-by-step explanation:
it is d because 28 and 32 =60 like your expression
The answer = 6.3 × 10-2
(scientific notation)
= 6.3e-2
(scientific e notation)
= 63 × 10-3
(engineering notation)
(thousandth; prefix milli- (m))
= 0.063
<span>(real number)</span>