The answer is in the picture. Click on it.
Answer:
I think it would be B.
Step-by-step explanation:
Since you aready have a 50% chance of landing on both heads or tails once. To land it on heads twice you would have a twenty five percent chance if you look at logic. in which my dad would often say. <u>Please mark the brainliest</u>
Answer:
p=5
Step-by-step explanation:
Please give brainliest
Answer:
4x+5y-34=0
Step-by-step explanation:
The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.
My goal is to put in in this form first. Then I will aim to put it in general form, ax+by+c=0.
So let's give it a go:
m is the change of y over the change of x.
To compute this I'm going to line my points up and subtract vertically, then put 2nd difference over 1st difference. Like this:
( 1 , 6)
-(6 , 2)
----------
-5 4
So the slope is 4/-5 or -4/5.
So m=-4/5.
Now we are going to find b given y=mx+b and m=-4/5 and we have a point (x,y)=(1,6) [didn't matter what point you chose here].
6=-4/5 (1)+b
6=-4/5 +b
Add 4/5 on both sides:
6+4/5=b
30/5+4/5=b
34/5=b
So the y-intercept is 34/5.
The equation in slope-intercept form is:
y=-4/5 x + 34/5.
In general form, it is sometimes the goal to make all of your coefficients integers so let's do that. To get rid of the fractions, I'm going to multiply both sides by 5. This clears the 5's that were on bottom since 5/5=1.
5y=-4x+34
Now add 4x on both sides:
4x+5y=34 This is standard form.
Subtract 34 on both sides:
4x+5y-34=0
Answer:
<em>after 4seconds</em>
Step-by-step explanation:
Given the height, h , in feet, of the football above the ground after t seconds expressed by h ( t ) = − 8 t^2 + 32 t, the height of the ball on the ground is 0feet.
Substitute h(t) = 0 into the expression and calculate t;
h ( t ) = − 8 t^2 + 32 t
0 = − 8 t^2 + 32 t
8t² = 32t
8t = 32
Divide both sides by 8
8t/8 = 32/8
<em>t = 4s</em>
<em>Hence the football hits the ground after 4seconds</em>
