Answer:
Vd = 1.597 ×10⁻⁴ m/s
Explanation:
Given: A = 3.90×10⁻⁶ m², I = 6.00 A, ρ = 2.70 g/cm³
To find:
Drift Velocity Vd=?
Solution:
the formula is Vd = I/nqA (n is the number of charge per unit volume)
n = No. of electron in a mole ( Avogadro's No.) / Volume
Volume = Molar mass / density ( molar mass of Al =27 g)
V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³
n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)
n= 6.02 × 10 ²⁸
Now
Vd = (6A) / ( 6.02 × 10 ²⁸ × 1.6 × 10⁻¹⁹ C × 3.9×10⁻⁶ m²)
Vd = 1.597 ×10⁻⁴ m/s
Answer:a) The linear speed of the rotating merry-go-round is 1.884 m/s.
b) The acceleration of the rotating merry-go-round device is 
.
Explanation:
a) linear speed of the device:
Distance =
Child seated 1.2 meters from the center, which means that radius ,r = 1.2 meters
Time taken to complete one revolution = 4.0 seconds
The linear speed of the rotating merry-go-round is 1.884 m/s.
b) Acceleration
Linear velocity ,v = 1.884 m/s
The acceleration of the rotating merry-go-round device is .
The force applied on the fly and the windshield are equal based on Newton's Law of Action and Reaction. the difference between them is that the fly's body does not have enough mechanical strength to withstand the force but the windshield does.
Answer: the amount of precious metals that could
be had.
<span>Mercantilism believed that a nation was rich based
on how big their reserves were for precious metals like gold and silver.
Exporting lots of gold and silver, during the time mercantilism was in place as
an economic system, exhibited a nation’s wealth. </span>
Answer:
The gravitational potential energy gained by the book is 30.4 J
Explanation:
The change in gravitational potential energy of an object is given by
where
m is the mass of the object
g is the acceleration of gravity
is the change in height of the object
For the book in this problem,
m = 2.0 kg
g = 9.8 m/s^2
Substituting into the equation, we find
