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Olin [163]
3 years ago
6

Which best describes her speed and velocity? (There are 60 seconds in 1 minute.) Her speed is 4.4 m/s, and her velocity is 0 m/s

. Her speed is 1.1 m/s, and her velocity is 0 m/s. Her speed is 0 m/s, and her velocity is 2400 m/s. Her speed is 4.4 m/s, and her velocity is 4.4 m/s.
Physics
2 answers:
olya-2409 [2.1K]3 years ago
8 0

Answer:

a

Explanation:

Georgia [21]3 years ago
6 0

Answer:

A

Explanation:

Yw :)

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Electric power is to be generated by installing a hydraulic turbine-generator at a site 120 m below the free surface of a large
iogann1982 [59]

Answer:

P = 2234400 Watt

Explanation:

Power generation is given as rate of work done

Here the turbine generator is located at 120 m below the free surface

So here rate of work done is given as rate of potential energy

Power = \frac{dw}{dt}

Power = \frac{mgh}{t}

so we have

Power = (\frac{dm}{dt})gh

now we have

Power = 1900(9.8)(120) = 2234400 Watt

so the power generation potential will be 2234400 Watt

8 0
3 years ago
If a marathon runner averages 9.51 mi/hr, how long does it take him to run a 26.220-mile marathon. Express your answers in hours
ASHA 777 [7]

Explanation:

Speed of the marathon runner, v = 9.51 mi/hr

Distance covered by the runner, d = 26.220 mile

Let t is the time taken by the marathon runner. We know that the speed of the runner is given by total distance divided by total time taken. Mathematically, it is given by :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{26.220\ mi}{9.51\ mi/hr}

t = 2.75 hours

Since, 1 hour = 60 minutes

t = 165 minutes

Since, 1 minute = 60 seconds

t = 9900 seconds

Hence, this is the required solution.

7 0
3 years ago
What keeps an inflated balloon from falling down if you rub it against your hair and place it against a wall? 1. rubbing distort
Keith_Richards [23]
2 because when you are doing this it causes friction Which then cause the balloon to stick
~dany-ley
3 0
3 years ago
If I measure the current to be 0.5 A and the voltage is 4.5 V. What is my Power?
Korvikt [17]
As we know that P=IV so P = (0.5A)(4.5V)
                                            P= 2.25 watt
6 0
3 years ago
A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc
ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

T=2\pi \sqrt{\frac{L}{g} }

Where T is period

           L is length of rod

       g is acceleration due to gravity =     9.8m/s^{2}

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this L_{O}

L_{O} = 3/4 * 5.95m

        = 4.4625m

thus   T=2\pi \sqrt{\frac{L_{O} }{g} }

          T=2\pi \sqrt{\frac{4.4625 }{9.8} }

          T= 4.24sec

8 0
4 years ago
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