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Kipish [7]
3 years ago
15

WILL GIVE BRAINLIEST. If 3x+5y=13 and 6x+7y=20, find the value of y/x

Mathematics
2 answers:
Illusion [34]3 years ago
8 0

Answer:

X  =  1

Y  =  2

Step-by-step explanation:

3x+5y=13

3(1)+5(2)=13

3+10

13

6x+7y=20

6(1)+7(2)=20

6+14

20

Scilla [17]3 years ago
3 0

Answer:

y= 2 x=1

Step-by-step explanation:

You may use the substitution or even the elimination method. Hoped that helped ;)

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A young sumo wrestler decided to go on a special diet to gain weight rapidly. He gained weight at a constar
Masteriza [31]

Answer:

  • <u>5.2 kg per month.</u>

<u></u>

Explanation:

The measure of how fast the wrestler gained weight, in kg per month, is the  weight gain rate.

The table is:

Time (months)           Weight (kg)

    0.5                             80.6

    2                                 88.4

    3.5                              96.2

The weight gain rate, WGR, for a period may be calculated as:

  • WGR = [ weight gain ] / [period]

  • WGR = [final weight - initial weight] / [final time - initial time]

  • WGR₁ = [88.4 kg - 80.6 kg] / [2 month - 0.5 month] = 7.8 kg / 1.5 month = 5.2 kg / month

  • WGR₂ = [96.2 kg - 88.4 kg] / [3.5 month - 2 month] = 7.8 kg / 1.5 month = 5.2 kg / month.

As you see, the wrestler gained weight at a constant rate of 5.2 kg per month.

7 0
3 years ago
Which rational exponent represents a cube root? A. 3/2 B. 1/2 C. 1/4 D. 1/3
diamong [38]

D. 1/3

A cube root can be written as an exponent: 1/3

\sqrt[3]{x} = x^{\frac{1}{3} }

5 0
3 years ago
Read 2 more answers
Answer<br><br> -10 – (-2) =
Allisa [31]

Answer:

8

Step-by-step explanation:

- (-2) is the same as + 2

-10 + 2 = -8

8 0
3 years ago
Read 2 more answers
Math:
Dahasolnce [82]

Answer:

a) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}, b) x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}, x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

\sqrt{3}\cdot \csc x - 2 = 0

\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0

\sqrt{3} - 2\cdot \sin x = 0

\sin x = \frac{\sqrt{3}}{2}

x = \sin^{-1} \frac{\sqrt{3}}{2}

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

b) The equation must be simplified first:

\cos x + 1 = - \cos x

2\cdot \cos x = -1

\cos x = -\frac{1}{2}

x = \cos^{-1} \left(-\frac{1}{2} \right)

Value of x is contained in the following sets of solutions:

x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i, \forall i \in \mathbb{N}_{O}

x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i, \forall i \in \mathbb{N}_{O}

7 0
3 years ago
Can sum one help me
sleet_krkn [62]

Answer:

help with what exactly

8 0
3 years ago
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