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3 years ago

What's the answer for number 4? And did I graph it right?

Mathematics

1 answer:

Fofino [41]3 years ago

6 0

Solution is (3,-3).

3x+y=6

x-intercept; y=0, x=2 (2,0)

y-intercept; x=0, y=6 (0,6)

2y-x=-9

x-intercept; y=0, x=9 (9,0)

y-intercept; x=0, y=-4.5 (0,-4.5)

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aflati masurile a doua unghiuri complementare stiind ca masura unuia dintre ele este cu 18° mai mica decat triplul masurii celui

Ahat [919]

Answer:

The angle is "27 and 63".

Step-by-step explanation:

Let A and B are two angles, in which A is " $\frac{1}{2}$ " complementary angles and B be is another complementary angle.

Condition of complementary angle :

$A+B =90 ......(i)$

Solution:

$\ A = \ 3B - 18 \\\\ \ put \ the \ value \ of \ A \ in \ equation.....(i) \\\\ \ Equation: \\ \\\Rightarrow \ A\ +\ B \ =\ 90 \\\\\Rightarrow \ 3B\ -\ 18 \ + \ B \ = \ 90 \\\\\Rightarrow \ 4B \ = \ 90 +18 \\\\\Rightarrow \ 4B = 108 \\\\ \Rightarrow B = \frac{108}{4} \\\\ \Rightarrow B \ = \ 27\\$

$\ put \ the \ value \ of \ B \ in \ equation (i).\\\\ \ Equation: \\\\\Rightarrow A+B=90\\\\\Rightarrow A+27=90\\\\\Rightarrow A=90-27\\\\\Rightarrow A= 63$

7 0

3 years ago

I need help from MATH 9 - Linear Relation 1: The slope and the y-intercept Form <img src="https://tex.z-dn.net/?f=y%3Dmx%2Bb%3A"

SashulF [63]

Answer:i think it is y-y1=m(x-x1)

m is herein undefined.

Slope, m, is defined as change-of-y divided by change-of-x...

m=(y-y1)/(x-x1)

The mathematical concept of undefined means that the denominator is zero. This means that both values of x are equal.

(-4,-8)

This equation is x=-4

It is a vertical line and includes the point of y=-8.

Step-by-step explanation:

8 0

3 years ago

«<br> In simplified form, V18 is _

zysi [14]

Answer:

3V2

Step-by-step explanation:

V18

V9 times 2 equals 18

V3 to the second power because 3 times 3=9 so we get 3V2

6 0

3 years ago

What are the divisible number(s) for 430?

ollegr [7]

Answer:

The numbers that 430 is divisible by are 1, 2, 5, 10, 43, 86, 215, and 430.

7 0

3 years ago

Read 2 more answers

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

lubasha [3.4K]

Answer:

a. 10.4 problems are expected to be resolved today, with a standard deviation of 1.44 problems.

b. 0.2457 = 24.57% probability 10 of the problems can be resolved today

c. 0.5137 = 51.37% probability 10 or 11 of the problems can be resolved today

d. 0.5017 = 50.17% probability more than 10 of the problems can be resolved today

Step-by-step explanation:

For each case, there are only two possible outcomes. Either they are solved, or they are not. Cases are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

It can resolve customer problems the same day they are reported in 80% of the cases.

This means that $p = 0.8$

Sample of 13 cases:

This means that $n = 13$

a. How many of the problems would you expect to be resolved today? What is the standard deviation?

Expected:

$E(X) = np = 13*0.8 = 10.4$

Standard deviation:

$\sqrt{V(X)} = \sqrt{13*0.8*0.2} = 1.44$

10.4 problems are expected to be resolved today, with a standard deviation of 1.44 problems.

b. What is the probability 10 of the problems can be resolved today?

This is $P(X = 10)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{13,10}.(0.8)^{10}.(0.2)^{3} = 0.2457$

0.2457 = 24.57% probability 10 of the problems can be resolved today.

c. What is the probability 10 or 11 of the problems can be resolved today?

This is $p = P(X = 10) + P(X = 11)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{13,10}.(0.8)^{10}.(0.2)^{3} = 0.2457$

$P(X = 11) = C_{13,11}.(0.8)^{11}.(0.2)^{2} = 0.2680$

$p = P(X = 10) + P(X = 11) = 0.2457 + 0.2680 = 0.5137$

0.5137 = 51.37% probability 10 or 11 of the problems can be resolved today.

d. What is the probability more than 10 of the problems can be resolved today?

This is

$P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13)$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 11) = C_{13,11}.(0.8)^{11}.(0.2)^{2} = 0.2680$

$P(X = 12) = C_{13,12}.(0.8)^{12}.(0.2)^{1} = 0.1787$

$P(X = 13) = C_{13,13}.(0.8)^{13}.(0.2)^{0} = 0.0550$

$P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) = 0.2680 + 0.1787 + 0.0550 = 0.5017$

0.5017 = 50.17% probability more than 10 of the problems can be resolved today

6 0

3 years ago