<h3>Given</h3>
- a rectangle x units wide and y units high divided into unit squares
<h3>Find</h3>
- The total perimeter of the unit squares, counting each line segment once
<h3>Solution</h3>
For each of the y rows of squares, there are x segments at the top, plus another x segments at the bottom. The total number of horizontal segments is then
... horizontal segment count = (y +1)x
Likewise, for each of the x columns of squares, there are y segments to the left, plus another y segments to the right of the entire area. Then the total number of vertical segments is
... vertical segment count = (x+1)y
The total segment count is ...
... total segments = horizontal segments + vertical segments
.. = (y+1)x +(x+1)y
... total segments = 2xy +x +y
_____
<u>Check</u>
We know a square (1×1) has 4 segments surrounding it.
... count = 2·1·1 +1 +1 = 4 . . . . (correct)
We know the 3×3 window in the problem statement has 24 segments.
... count = 2·3·3 +3 +3 = 18 +3 + 3 = 24 . . . . (correct)
We know a 1×3 row of panes will have 10 frame elements.
... count = 2·1·3 +1 +3 = 6 +1 +3 = 10
It looks like our formula works well.
Answer:
The answer would be, 2.75
Step-by-step explanation:
Add all the numbers up:
0+1+1+2+3+4+5+6=22
Divide the answer by the amount of numbers:
22÷8=2.75
Answer: 1,000,000,000*10
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Answer:
Step-by-step explanation:
• AB, BC, and AC form a triangle. Enter a possible value of AC....
So it asks for only a possible value of AC as there are many possible values.
Given AB = 8 cm and BC = 6 cm, they are in the ratio of 3:4.
Line segments of 3, 4 and 5 length will form a right-angled triange.
A possible value of AC = 5*2 = 10cm
• Points A, B, and C lie on the same line, and C lies between A and B.
So AC+CB = AB
AC+6 = 8
AC = 2cm
Enter this value of AC in the second
response box.
The method to use to prove that triangle AOB is congruent to triangle AOC is SSS.
