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dexar [7]
3 years ago
10

Which of the following are not phases of matter?

Chemistry
2 answers:
german3 years ago
7 0

A. Mixture and D. Compound

Vikentia [17]3 years ago
3 0
Mixture and Compound

If ever needed there are only 4 states of matter those include: Solid,Liquid,Gas, and Plasma
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What is the molarity of 50gram of calcium carbonate is dissolved in 250ML of water​
m_a_m_a [10]

Answer:

Molar Mass of Calcium Carbonate = 100g

given mass = 50g

Number of mole of Calcium Carbonate =50/100 = 0.5 mole

Molarity = mole per litre of volume

Molarity = 0.5 /0.25 = 2mole/litre

Explanation:

hope it helps ......

mark me as brainliest ❤️

7 0
3 years ago
Read 2 more answers
CO, + H2O –H^2 CO^3 The reaction is which type of chemical reaction?​
gulaghasi [49]

Answer:

Combination reaction or synthesis reaction

Explanation:

Given reaction:

                 CO  +  H₂O  →  H₂CO₃

The type of reaction shown above is a combination or synthesis reaction. A combination reaction is one in which a single product is formed from two or more reactants.

In the given reaction carbon monoxide combines with water to produce hydrogen carbonate.

The formation of compounds from the union of their constituent elements falls into this category of reactions.

4 0
2 years ago
16 Which two gases can not be broken down by chemical means?(1) CO and He (3) Xe and He
lyudmila [28]
The answer is (2) CO and NH3. The chemical reaction can only break down chemical bonds between atoms inside the molecule. The He and Xe is consists of one atom only, so they can not be broken down by chemical means.
4 0
3 years ago
What is the molecular formula of a compound if its empirical formula is CFBrO and its molar mass is 381.01 g/mol?
Katarina [22]
A(C)+A(F)+A(Br)+A(O)=12.01+19.00+79.90+16.00=126.91

n=381.01/126.91= 3

C₃F₃Br₃O₃
4 0
2 years ago
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What volume of a 0.3300M solution of sodium hydroxide would br ruired to titrate 15.00 mL of 0.1500 M oalic Acid?
Ganezh [65]

Answer:

3.41 mL

Explanation:

At equivalence point  from the reaction given,

Moles of Oxalic\ Acid = 2 × Moles of NaOH

Considering

Molarity_{Oxalic\ Acid}\times Volume_{Oxalic\ Acid}=2\times Molarity_{NaOH}\times Volume_{NaOH}

Given  that:

Molarity_{NaOH}=0.3300\ M

Volume_{NaOH}=?

Volume_{Oxalic\ Acid}=15.00\ mL

Molarity_{Oxalic\ Acid}=0.1500\ M

So,  

Molarity_{Oxalic\ Acid}\times Volume_{Oxalic\ Acid}=2\times Molarity_{NaOH}\times Volume_{NaOH}

2\times 0.3300\times Volume_{NaOH}=0.1500\times 15.00

Volume_{NaOH}=3.41\ mL

4 0
3 years ago
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