Which statements correctly describe thermal energy in a block of ice, a glass of liquid water, and a container of steam?

Your calculated density of aluminum is d = 2.69 g/cm3. Aluminum’s accepted density is 2.70 g/cm3. Without writing the "%" sign,

stepan [7]

Answer:

0.37 %

Explanation:

Given that:

Calculated density of aluminum = 2.69 g/cm³

Accepted density of aluminum = 2.70 g/cm³

$Error\ percentage=\frac {|Accepted\ value-Calculated\ value|}{Accepted\ value}\times 100$

Thus, applying values as:

$Error\ percentage=\frac {|2.70-2.69|}{2.70}\times 100$

<u>Percent error = 0.37 %</u>

7 0

3 years ago

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Given that a for HCN is 6. 2×10^−10 at 25 °C. What is the value of b for cn− at 25 °C?

Kay [80]

If Ka for HCN is 6. 2×10^−10 at 25 °C, then the value of Kb for cn− at 25 °C is 1.6 × 10^(-5).

<h3>What is base dissociation constant? </h3><h3 />

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 6.2× 10^(-10)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{6.2×10^(-10) }

= 1.6× 10^(-5)

Thus, the value of base dissociation constant at 25°C is 1.6 × 10^(-5).

learn more about base dissociation constant :

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4 0

2 years ago

What is the mole fraction of each component if 3.9 g of benzene (C6H6) is dissolved in 4.6 g of toluene (C7H8)

Savatey [412]

Answer:

Step 1 of 6

(a)

The mass of benzene is , so calculate the moles of benzene as follows:

The mass of toluene is, so calculate the moles of toluene as follows:

Now, calculate the mole fraction as follows:

Therefore, the mole fraction of benzene and toluene is and respectively.

Step 2 of 6

(b)

The formula to calculate the partial pressure is as follows:

Here, is the partial pressure of benzene, is the vapour pressure of pure benzene and is the mole fraction of benzene.

Vapour pressure of pure benzene at is.

Substitute the values in the equation as follows:

Therefore, the partial pressure is .

Step 3 of 6

(c)

Vapor pressure of the solution at 1 atm is .

When the total pressure of the vapour pressure of the mixture is at a temperature, then, the solution boils. It corresponds to the boiling point of the solution.

Calculate the total pressure of the solution at as follows:

Since, the total pressure is less than the atmospheric pressure, the solution will not boil at .

Calculate the total pressure of the solution at as follows:

Since, the total pressure is greater than the atmospheric pressure, the solution will boil at .

Therefore, the boiling point of the solution is .

Step 4 of 6

(d)

Mole fraction of benzene at is calculated as follows:

Mole fraction of toluene at is calculated as follows:

Therefore, the mole fractions of benzene and toluene are and respectively.

Step 5 of 6

(e)

Vapor pressure of benzene at is .

Partial pressure of benzene is calculated as follows:

Vapor pressure of toluene at is .

Partial pressure of toluene is calculated as follows:

Step 6 of 6

Weight composition of the vapour that is in equilibrium with the solution is calculated as follows:

Explanation:

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4 0

3 years ago

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DDT, an insecticide harmful to fish, birds, and humans, is produced by the following reaction. 2 C6H5Cl + C2HOCl3 → C14H9Cl5 + H

Elena-2011 [213]

Answer:

1,070.41 grams of DDT will be formed .Explanation:

1) $2 C_6H_5Cl + C_2HOCl_3\rightarrow C_{14}H_9Cl_5 + H_2O$

Moles of chlorobenzene = $\frac{1197 g}{112.5 g/mol}=10.64 mol$

According to reaction, 2 moles of chloro benzene reacts with 1 mole of chloral . Then 10.64 moles of chloro benzene will react with :

$\frac{1}{2}\times 10.64 mol=5.32 mole$ of chloral

2) Moles of chloral = $\frac{456 g}{147.5 g/mol}=3.0915 mol$

According to reaction, 1 moles of chloral reacts with 2 mole of chlorobenzene . Then 3.0915 moles of chloral will react with :

$\frac{2}{1}\times 3.0915 mol=6.1830 mol$ of chloro benzene

As we can see that chloral is in limiting amount and chloro benzene is in excessive amount. So, amount of DDT will depend upon amount of chloral.

According to reaction, 1 mole chloral gives 1 mole DDT.Then 3.0195 moles of chloral will give :

$\frac{1}{1}\times 3.0195 mol=3.0195 mol$

Mass of 3.0195 moles of DTT :

3.0195 mol × 354.5 g/mol = 1,070.41 g

1,070.41 grams of DDT will be formed .

3 0

3 years ago

Write a nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90.

rusak2 [61]

Answer:

235/92U+10n→144/54Xe+90/38Sr+2/10n

Explanation:

The nuclear reaction for the neutron-induced fission of u−235 to form xe−144 and sr−90 is represented by;

235/92U+10n→144/54Xe+90/38Sr+2/10n

In nuclear fission reactions a heavy nuclide is split into two light nuclides and is coupled by the release of energy.

3 0

3 years ago