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Scrat [10]
3 years ago
7

Which statements correctly describe thermal energy in a block of ice, a glass of liquid water, and a container of steam?

Chemistry
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

Steam always has more thermal energy than ice.

Explanation:

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How many grams of oxygen would be needed to completely react with 18 grams of methane (CH4)?
S_A_V [24]

Answer:

35.91 grams of oxygen

Explanation:

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3 years ago
Is carbon monoxide an element a compound a heterogeneous mixture or a homogeneous mixture?
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Answer:  Carbon monoxide, or "CO", is a compound.  This is a homogeneous compound (not a mixture).
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3 years ago
An electron moved from a higher energy level to a lower energy level. What most likely happened during the transition? (4 points
Alex787 [66]

Answer: The anwser is A a photon was realeased please mark brainliest

Explanation:

6 0
2 years ago
Read 2 more answers
A 20.0 g piece of a metal is heated and place into a calorimeter containing 250.0 g of water initially at 25.0 oC. The final tem
BartSMP [9]

Answer:

Q_{metal} = -6799\,J

Explanation:

By the First Law of Thermodynamics, the piece of metal and water reaches thermal equilibrium when water receives heat from the piece of metal. Then:

Q_{metal} = - Q_{w}

Q_{metal} = m_{w} \cdot c_{p,w}\cdot (T_{1}-T_{2})

Q_{metal} = (250\,g)\cdot \left(4.184\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (25\,^{\textdegree}C - 31.5\,^{\textdegree}C)

Q_{metal} = -6799\,J

6 0
3 years ago
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How many joules of heat must be absorbed by 500g h2O @ 50CELCIUS to convert to steam @ 120 celcius?
nadya68 [22]

Answer:

Q = 1267720 J

Explanation:

  • Qt = QH2O + ΔHv

∴ QH2O = mCpΔT

∴ m H2O = 500 g

∴ Cp H2O = 4.186 J/g°C = 4.183 E-3 KJ/g°C

∴ ΔT = 120 - 50 = 70°C

⇒ QH2O = (500 g)(4.183 E-3 KJ/g°C)(70°C) = 146.51 KJ

∴ ΔHv H2O = 40.7 KJ/mol

moles H2O:

∴ mm H2O = 18.015 g/mol

⇒ moles H2O = (500 g)(mol/18.015 g) = 27.548 mol H2O

⇒ ΔHv H2O = (40.7 KJ/mol)(27.548 mol) = 1121.21 KJ

⇒ Qt = 146.51 KJ + 1121.21 KJ = 1267.72 KJ = 1267720 J

5 0
3 years ago
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