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Sergeu [11.5K]
3 years ago
10

12 *

Chemistry
1 answer:
nikitadnepr [17]3 years ago
7 0

Answer:

true

Explanation:

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For the reaction COCl2(g)⇌CO(g)+Cl2(g), K= 2.19×10−10 at 373 K
vladimir1956 [14]

Answer:

D) The equilibrium lies far to the left

Explanation:

According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:

K = \frac{[CO][Cl_{2}]}{[COCl_{2}]} = 2.19×10^{-10}

([X] means = concentration of X)

This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.

6 0
3 years ago
When work is done on an object, the amount of ________ it has changes.
arsen [322]
Hey there!

When work is done on an object, the amount of energy it has changes.

Hope this helps!

~Autumly
3 0
3 years ago
How much work is required to lift a 0.500 kg block 18.5 m?
kipiarov [429]

Answer:

Work = 90.65 j

Explanation:

Given data:

Mass = 0.500 Kg

Distance = 18.5 m

Work done = ?

Solution:

Work = force . distance

Force = mg

Work = mg.distance

Work = mgh

Work = 0.500 Kg × 9.8 m/s²× 18.5 m

Work = 90.65 Kg .m²/s²

Kg .m²/s² = j

Work = 90.65 j

3 0
3 years ago
Reaction time is a stimulus reaponse ______ ? A ) instant B) complex. C) simple . D) automatic
lina2011 [118]
Reactions happen instantly even if some are slower than others they all happen instantly so the answer would be A.
5 0
3 years ago
Read 2 more answers
An electrochemical cell is powered by the half reactions shown below.
andrezito [222]
Reduction reactions are those reactions that reduce the oxidation number of a substance. Hence, the product side of the reaction must contain excess electrons. The opposite is true for oxidation reactions. When you want to determine the potential difference expressed in volts between the cathode and anode, the equation would be: E,reduction - E,oxidation. 

To cancel out the electrons, the e- in the reactions must be in opposite sides. To do this, you reverse the equation with the negative E0, then replacing it with the opposite sign. 

Pb(s) --> Pb2+ +2e-      E0 = +0.13 V
Ag+ + e-  ---> Ag           E0 = +0.80 V

Adding up the E0's would yield an overall electric cell potential of +0.93 V.
7 0
3 years ago
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