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natima [27]
3 years ago
10

How would Mg change to gain a noble gas structure? lose 2 electrons gain 6 electrons

Chemistry
2 answers:
Gekata [30.6K]3 years ago
4 0
Are those the answers 
 hah because i got a little confused 

Paladinen [302]3 years ago
4 0

Answer: Magnesium atom looses 2 electrons to obtain the noble gas structure.

Explanation:

Atomic number of magnesium is 12. Electronic configuration of magnesium :

[Mg]=1s^22s^22p^63s^2

In the periodic table, the nearest noble gas to magnesium element is Neon with atomic number 10.

[Ne]=1s^22s^22p^6

So, in order to obtain noble gas electronic configuration the magnesium atom will loose 2 electrons.

[Mg^{2+}]=1s^22s^22p^6

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8 0
3 years ago
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Given 6 moles of CuCl2, how many moles of AlCl, were made? SHOW the math below​
Anastasy [175]

Answer:

6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

Explanation:

Given data:

Moles of CuCl₂ = 6 mole

Moles of AlCl₃ produced = ?

Solution:

3CuCl₂ + 2Al → 2AlCl₃ + 3Cu

Now we will compare the moles of CuCl₂ with AlCl₃ .

            CuCl₂        :        AlCl₃

                3            :          2

                6           :         2/3 ×6 = 4 mol

So, 6 moles of CuCl₂  will produced 4 moles of  AlCl₃ .

6 0
3 years ago
Which unit can be used to express the rate of a reaction?
Ugo [173]
<span>A) mL / s

This is the amount of milliliters per second</span>
4 0
3 years ago
Read 2 more answers
When a saturated solution of NH4Br dissolved in 100 grams of water is cooled from 60°C to 30°C, how much NH4Br will precipitate?
stepladder [879]

Answer:

m_{precipitated}=24.8g

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g

Best regards.

8 0
3 years ago
An atom of a particular element is traveling at 1.00% of the speed of light. The de Broglie wavelength is found to be 3.31 × 10-
ExtremeBDS [4]

Answer:

The given atom is of Ca.

Explanation:

Given data:

Speed of atom = 1% of speed of light

De-broglie wavelength = 3.31×10⁻³ pm (3.31×10⁻³ / 10¹² = 3.31×10⁻¹⁵ m)

What is element = ?

Solution:

Formula:

m = h/λv

m = mass of particle

h  = planks constant

v = speed of particle

λ = wavelength

Now we will put the values in formula.

m = h/λv

m = 6.63×10⁻³⁴kg. m².s⁻¹/3.31×10⁻¹⁵ m ×( 1/100)×3×10⁸ m/s

m = 6.63×10⁻³⁴kg. m².s⁻¹/ 0.099×10⁻⁷m²/s

m = 66.97×10⁻²⁷ Kg/atom

or

6.69×10⁻²⁶ Kg/atom

Now here we will use the Avogadro number.

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Now in given problem,

6.69×10⁻²⁶ Kg/atom × 6.022 × 10²³ atoms/ mol × 1000 g/ 1kg

40.3×10⁻³×10³g/mol

40.3  g/mol

So the given atom is of Ca.

8 0
2 years ago
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