How would Mg change to gain a noble gas structure? lose 2 electrons gain 6 electrons
2 answers:
Answer: Magnesium atom looses 2 electrons to obtain the noble gas structure.
Explanation:
Atomic number of magnesium is 12. Electronic configuration of magnesium :
In the periodic table, the nearest noble gas to magnesium element is Neon with atomic number 10.
So, in order to obtain noble gas electronic configuration the magnesium atom will loose 2 electrons.
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Answer:
Explanation:
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In this case, since these problems about gas mixtures are based off Dalton's law in terms of mole fraction, partial pressure and total pressure, we can write the following for hydrogen, we are given its partial pressure:
And can be solved for the total pressure as follows:
However, we first calculate the mole fraction of hydrogen by subtracting that of nitrogen to 1 due to:
Then, we can plug in to obtain the total pressure:
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<u>Answer:</u> The amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of hex-3-ene = 5.84 g
Molar mass of hex-3-ene = 82.14 g/mol
Putting values in equation 1, we get:
The chemical equation for the conversion of hex-3-ene to 3-hexanol follows:
By Stoichiometry of the reaction:
1 mole of hex-3-ene produces 1 mole of 3-hexanol
So, 0.0711 moles of hex-3-ene will produce = of 3-hexanol
Now, calculating the mass of 3-hexanol from equation 1, we get:
Molar mass of 3-hexanol = 102.2 g/mol
Moles of 3-hexanol = 0.0711 moles
Putting values in equation 1, we get:
To calculate the percentage yield of 3-hexanol, we use the equation:
Experimental yield of 3-hexanol = 4.33 g
Theoretical yield of 3-hexanol = 7.27 g
Putting values in above equation, we get:
Hence, the amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %