Can someone help me solve this

Mila [183]

First we need to have same units before comparing them. That is, either both of them are in cm or both of them are in mm. So if we need to convert 12.5 cm to mm, we know that 1 cm =10 mm. So we have to find out how many mm are in 12.5 cm. And let 12.5 cm =x mm. So to find the value of x , we set a proportion and solve for x. That is

$\frac{1cm}{10mm}=\frac{12.5cm}{x mm}$

The units cancel out and we do cross multiplication. That is

$1*x =12.5*10$

x=125

So 12.5 cm =125 mm. Therefore the correct proportion is C.

3 0

3 years ago

Y=-2х - 4 y=x - 5 how many solutions does this have

spayn [35]

Answer:

one solution

Step-by-step explanation:

-2x - 4 = x - 5

-3x - 4 = -5

-3x = -1

x = 1/3

y = 1/3 - 5

y = 1/3 - 15/3

y = -14/3

(1/3, -14/3)

5 0

3 years ago

Terry sees this offer refurbished phone 35% off now only ?78 what was the original price

Ronch [10]

Answer:

$223.

Step-by-step explanation:

Let x be the original price of phone.

We are told that Terry sees this offer refurbished phone 35% off now only $78.

We need to find x such that 35% of x is 78. We can represent this information as:

$\frac{35}{100} x=78$

$0.35 x=78$

$x=\frac{78}{0.35}$

$x=222.8571428571428571\approx 223$

Therefore, the original price of phone was $223.

3 0

3 years ago

Find the value of x in this equation. 25(4x − 3) − 2x = 45 − x

Charra [1.4K]

Answer:

x=40/33

Step-by-step explanation:

Let's solve your equation step-by-step.

25(4x−3)−2x=45−x

Step 1: Simplify both sides of the equation.

25(4x−3)−2x=45−x

(25)(4x)+(25)(−3)+−2x=45+−x(Distribute)

100x+−75+−2x=45+−x

(100x+−2x)+(−75)=−x+45(Combine Like Terms)

98x+−75=−x+45

98x−75=−x+45

Step 2: Add x to both sides.

98x−75+x=−x+45+x

99x−75=45

Step 3: Add 75 to both sides.

99x−75+75=45+75

99x=120

Step 4: Divide both sides by 99.

99x

99

=

120

99

x=

40

33

Answer:

x=40/33

7 0

3 years ago

Read 2 more answers

a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.

Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = 6.15 N

Hence, The effort applied = 6.15 N

Hope this answer helped you..

Please mark me as brainliest

8 0

1 year ago