Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
Answer:
5 word problems(4points each) & 10 open (3 points each)
Step-by-step explanation:
O= open response
W= word problems
W+O =15
4W + 3O = 50
multiply the first by -3 to eliminate O
-3W -3O = -45
4W + 3O = 50
AD BOTH
W = 5 ( 5 questions word problems)
O= 10 ( 10 questions open response)
5x4 = 20
10x3 = 30
20 + 30 = 50 points
Answer:you multiply the decimal by the number behind the decimal
Step-by-step explanation:
6.00
6.00x100
6
Its 47/8 hope this helped all you need to do is keep the 8 like how it is and then you do 5 times 8 and add 7 thats it
Answer:
2 possible values
Step-by-step explanation:
The given expression is:
![\sqrt[3]{\frac{144}{y} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B144%7D%7By%7D%20%7D)
In order for this to result in a whole number, 144/y must be a perfect cube, the possible perfect cubes (under 144) are:
1, 8, 27, 64, 125
The values of y that would result in those numbers are:
Only two values of y are integers, therefore, there are only two possible values of y for which the given expression results in a whole number.
