Answer:εδΑΒΓΒΕ
![U4\leq \sqrt{x} \sqrt[n]{x} 64](https://tex.z-dn.net/?f=U4%5Cleq%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%2064)
Step-by-step explanation:
73hsay is a little bit too long and ∩679∨78ω8㏒∴≠÷±
Answer:
answer is 57.
Step-by-step explanation:
Given
m<6= x - 8
m<7 = 2x - 7
We know
<6 + <7 = 180° [ being linear pair ]
x - 8 + 2x - 7 = 180°
3x - 15 = 180°
3x = 180° + 15°
3x = 195°
x = 195° / 3
x = 65°
Now
m<6= x - 8 = 65° - 8° = 57°
hope it helps :)
Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is

Since there are n logs in the pile, so we get

Thus, the total number of logs in the pile is 6.
Add 13 to both sides
13 = 2x + 15x
Simplify right side
13 = 17x
Divide through by 17
13/17 = x
Answer:
Factor by grouping
(2x+3) (x-5)
Step-by-step explanation: