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Sav [38]
3 years ago
6

Find I. Choose the correct answer. Amount Financed (m) = $1,400 Number of Payments per year (y) = 12 Number of Payments (n) = 24

Total Interest (c) = $200.50
I =
Mathematics
2 answers:
kirill115 [55]3 years ago
8 0
Hi there!

The answer to your problem is I = 13.7%

Your friend, ASIAX
Ugo [173]3 years ago
3 0
If m is the amount financed and P is the periodic payment, m = P\cdot\dfrac{1 - v^{n}}{i}. This is the standard formula for periodic payment over time for level interest. You are given m = 1400 You are given n = 24 You are ALMOST given P. You can figure it out. P = (1400 + 200.50)/24 = 1600.50/24 = 66.69 You're almost done. There are two things yet to do.
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Natalie is buying potatoes at the grocery store. If she buys 6 potatoes that each have a mass of 375 grams, what is the total ma
Natali [406]
Mass of one potato = 375 g
Mass of 6 potatoes = 375*6
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2.25 Kg
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You have 7 times as many nickels
vaieri [72.5K]

Answer:

16 +7= 23

Step-by-step explanation:

it's a addition problem

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2 years ago
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Can anyone solve this for me????
sweet-ann [11.9K]

The old rate of pay is x and the new rate is y then we have:

y = 2x + 7

Y = 21

PART 1:  21 = 2x+7

Subtract 7 from each side:

14 = 2x

Divide both sides by 2:

X = 14 / 2

X = 7

PART 2: The internship pays $7 per hour.

7 0
3 years ago
. Let X and Y be random variables of possible percent returns (0%, 10%,
bazaltina [42]

(a) The marginal distribution of <em>X</em> is

Pr(<em>X</em> = <em>x</em>) = ∑ Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>)

… = 0.0625 + 0.0625 + 0.0625 + 0.0625

… = 0.25

That is, the first equality follows from the law of total probability, with the sum taken over <em>y</em> from {0, 5, 10, 15}. Each probability Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>) is given in the table to be 0.0625.

Similarly, the marginal distribution of <em>Y</em> is

Pr(<em>Y</em> = <em>y</em>) = 0.25

(b) Yes, they're independent because

Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>) = 0.0625,

and

Pr(<em>X</em> = <em>x</em>) Pr(<em>Y</em> = <em>y</em>) = 0.25 • 0.25 = 0.0625.

(c) The mean of <em>X</em> is

E[<em>X</em>] = ∑ <em>x</em> Pr(<em>X</em> = <em>x</em>)

… = 0.25 ∑ <em>x</em>

<em>… </em>= 0.25 (0 + 5 + 10 + 15)

… = 7.5

and you would find the same mean for <em>Y</em>,

E[<em>Y</em>] = 7.5

The variance of <em>X</em> is

V[<em>X</em>] = E[<em>X</em>^2] - E[<em>X</em>]^2

… = (∑ <em>x</em>^2 Pr(<em>X</em> = <em>x</em>)) - 7.5^2

… = 0.25 (∑ <em>x</em>^2) - 56.25

… = 0.25 (0^2 + 5^2 + 10^2 + 15^2) - 56.25

… = 31.25

and similarly,

V[<em>Y</em>] = 31.25

(each sum is taken with <em>x</em> and <em>y</em> from {0, 5, 10, 15})

7 0
3 years ago
What are the values of the plots on the number lines?
Elina [12.6K]

Answer:

14. - 15

Step-by-step explanation:

The first one is located at 14. The second one is located at - 15

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2 years ago
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