Find the inverse of f(x)=2x-3.
1) replace "f(x)" with "y." Then y=2x-3.
2) interchange x and y. Then x=2y-3. x+3
3) solve this result for y. Then 2y=x+3, or y=----------------
2
-1 -1 x+3
4) replace y with f (x): f (x) = ---------
2
This is the procedure, with the answer given.
The slope of the line of best fit to the raw-score scatter plot is 0.98
- The equation is y = 0.98x - 3.74
- The value of y given that x = 12 is 8.02
<h3>How to determine the slope of the line?</h3>
From the question, we have the following parameters that can be used in our computation:
- Standard deviations of X, Sx = 1.88
- Standard deviations of Y, Sy =2.45
- Correlation coefficient, r between X and Y = 0.75
The slope (b) of the line is calculated as
b = r * Sy/Sx
Substitute the known values in the above equation, so, we have the following representation
b = 0.75 * 2.45/1.88
Evaluate
b = 0.98
<h3>The equation of the line of best fit</h3>
A linear equation is represented as
y = bx + c
Where
Slope = b
y-intercept = c
In (a), we have
b = 0.98
So, we have
y = 0.98x + c
Recall that the point (13, 9) is on the line of best fit.
So, we have
9 = 0.98 * 13 + c
This gives
9 = 12.74 + c
Evaluate
c = -3.74
So, we have
y = 0.98x - 3.74
<h3>The value of y from x</h3>
Here, we have
x = 12
So, we have
y = 0.98 x 12 - 3.74
Evaluate
y = 8.02
Read more about line of best fit at
brainly.com/question/1564293
#SPJ1
Answer:
the value of the investment after 3 years= £11,904
Step-by-step explanation:
sarah invests £9600 at a simple interest rate of 8% per year
number of years = 3
Formula for simple interest
I = P*n* r
P is the initial amount invested= 9600
r is the rate of interest = 8% = 0.08
n = number of years = 3
Now we find interest using formula
I = 9600 * 0.08 * 3= 2304
Interest amount is 2,304
Now we add the interest with the initial amount to get the value of investment after 3 years
9600 + 2304= 11904
Answer:
2h and 39mins
Step-by-step explanation:
If you are unsure of these times questions. I suggest you draw a timeline! it helps! Trust me!!
Answer:
.35 per minute. single variables.