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3 years ago

Which sequence of atomic numbers represents elements which have similar chemical properties

Chemistry

2 answers:

VashaNatasha [74]3 years ago

3 0

A rule of thumb is that elements in the same column or "group" have similar chemical properties. Answer D. has four elements that are all in group 2, or the "alkaline earth metals". The answer is D. 4, 20, 38, 88

Ksenya-84 [330]3 years ago

3 0

Answer: The correct answer is Option 4.

Explanation:

Elements that belong to the same group have similar chemical properties because they have same number of valence electrons.

For the given options:

Option 1: 19, 23, 30, 36

Element having atomic number 19 belongs to Group 1 of the periodic table.

Element having atomic number 23 belongs to Group 5 of the periodic table.

Element having atomic number 30 belongs to Group 12 of the periodic table.

Element having atomic number 36 belongs to Group 18 of the periodic table.

Thus, these elements will not show similar chemical properties.

Option 2: 9, 16, 33, 50

Element having atomic number 9 belongs to Group 17 of the periodic table.

Element having atomic number 16 belongs to Group 16 of the periodic table.

Element having atomic number 33 belongs to Group 15 of the periodic table.

Element having atomic number 50 belongs to Group 14 of the periodic table.

Thus, these elements will not show similar chemical properties.

Option 3: 3, 12, 33, 40

Element having atomic number 3 belongs to Group 1 of the periodic table.

Element having atomic number 12 belongs to Group 2 of the periodic table.

Element having atomic number 33 belongs to Group 15 of the periodic table.

Element having atomic number 40 belongs to Group 4 of the periodic table.

Thus, these elements will not show similar chemical properties.

Option 4: 4, 20, 38, 88

Element having atomic number 4 belongs to Group 2 of the periodic table.

Element having atomic number 20 belongs to Group 2 of the periodic table.

Element having atomic number 38 belongs to Group 2 of the periodic table.

Element having atomic number 88 belongs to Group 2 of the periodic table.

Thus, these elements will show similar chemical properties.

Hence, the correct answer is Option 4.

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Answer: There are 0.5 grams of barium sulfate are present in 250 of 2.0 M $BaSO_{4}$ solution.

Explanation:

Given: Molarity of solution = 2.0 M

Volume of solution = 250 mL

Convert mL int L as follows.

$1 mL = 0.001 L\\250 mL = 250 mL \times \frac{0.001 L}{1 mL}\\= 0.25 L$

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3 years ago

What is the difinition of the word democracy?

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2 years ago

Read 2 more answers

The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem

Blababa [14]

Answer : The correct option is, pressure.

Explanation :

The ideal gas equation is,

$PV=nRT$

where,

P = pressure of the gas

V = volume of the gas

n = number of moles of gas

T = temperature of the gas

R = gas constant

The value of 'R' has several different values which are :

$R=0.08205L.atm/mol.K$

$R=8.3145L.kPa/mol.K$

$R=8.3145J/mol.K$

$R=1.987cal/mol.K$

$R=0.08314L.bar/mol.K$

That means, the value of 'R' is different due the change in the pressure value and all the variables (temperature, volume and moles) are constant.

Hence, the correct option is, pressure.

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3 years ago

Calculate the heat absorbed by the water in a calorimeter when 175 grams of lead cools from 125.0°C to 22.0°C. The specific heat

Iteru [2.4K]

Answer:

Q = 233.42 J

Explanation:

Given data:

Mass of lead = 175 g

Initial temperature = 125.0°C

Final temperature = 22.0°C

Specific heat capacity of lead = 0.01295 J/g.°C

Heat absorbed by water = ?

Solution:

Heat absorbed by water is actually the heat lost by the metal.

Thus, we will calculate the heat lost by metal.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 22.0°C - 125.0°C

ΔT = -103°C

Q = 175 g × 0.01295 J/g.°C×-103°C

Q = -233.42 J

Heat absorbed by the water is 233.42 J.

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