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3 years ago

What size container should you use when mixing chemicals

Chemistry

1 answer:

NNADVOKAT [17]3 years ago

5 0

My professor told me to use a 500ml beaker depending on what your mixing.

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70 points and will give brainliest

ikadub [295]

Answer:

74mL

Explanation:

Given parameters:

Molar mass of citric acid = 192g/mol

Molar mass of baking soda = 84g/mol

Concentration of citric acid = 0.8M

Mass of baking powder = 15g

Unknown parameters:

Volume of citric acid = ?

Solution

Equation of the reaction:

C₆H₈O₇ + 3NaHCO₃ → Na₃C₆H₅O₇ + 3H₂O + 3CO₂

Procedure:

We work from the known parameters to the unknown. From the statement of the problem, we can approach the solution from the parameters of the baking powder.
From the baking powder, we can establish a molar relationship between the two reactants. We employ the mole concept in this regard.
We find the number of moles of the baking powder that went into the reaction using the expression below:

Number of moles = $\frac{mass}{molar mass}$

Number of moles = $\frac{15}{84}$ = 0.179mole

From the equation of the reaction, we can find the number of moles of the citric acid:

3 moles of baking powder reacted with 1 mole of citric acid

0.179 moles of baking powder would react with $\frac{0.179}{3}$ :

This yields 0.059mole of citric acid

To find the volume of the citric acid, we use the mole expression below:

Volume of citric acid = $\frac{number of moles}{concentration}$

Volume of citric acid = $\frac{0.059}{0.8}$ = 0.074L

Expressing in mL gives 74mL

4 0

3 years ago

Suppose you used 0.5 M NaOH to titrate your vinegar sample instead of 0.1 M. What effect does the concentration of base added ha

laiz [17]

Answer: the reliability will be worse

Explanation:

Suppose we used 0.5 M NaOH to titrate our vinegar sample instead of 0.1 M.

Now by using 0.5M instead of 0.1M we are increasing the concentration of NaOH,

We know that the moles used = Volume x concnetration.

so for the same no of moles, if the concentration increases, the volume decreases.

Hence it will consume less NaOH.

now Since the volume decreases, the titration volume of less number will increase the % error.

Therefore the reliability will be worse.

4 0

2 years ago

Jim and Jan were racing in a 400 meter event. Jim ran the race in 44.32 seconds. Jan ran the race in 42.21 seconds. Calculate th

nordsb [41]

Answer:

2.11

Explanation:

44.32- 42.21=2.11

Hope this helps

4 0

3 years ago

Read 2 more answers

This chemical equation is balanced.

alina1380 [7]

Answer:

Explanation:

6 0

3 years ago

A 12.0% sucrose solution by mass has a density of 1.05 gem, what mass of sucrose is present in a 32.0-mL sample of this solution

natulia [17]

Answer:

Option C. 4.03 g

Explanation:

Firstly we analyse data.

12 % by mass, is a sort of concentration. It indicates that in 100 g of SOLUTION, we have 12 g of SOLUTE.

Density is the data that indicates grams of solution in volume of solution.

We need to determine, the volume of solution for the concentration

Density = mass / volume

1.05 g/mL = 100 g / volume

Volume = 100 g / 1.05 g/mL → 95.24 mL

Therefore our 12 g of solute are contained in 95.24 mL

Let's finish this by a rule of three.

95.24 mL contain 12 g of sucrose

Our sample of 32 mL may contain ( 32 . 12) / 95.24 = 4.03 g

7 0

3 years ago