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adoni [48]
2 years ago
9

) Please circle the valid statement(s) associated with an adiabatic process, a reversible process, and an isentropic process of

a closed system. (A) A reversible, adiabatic process is an isentropic process. (B) The entropy generation of a reversible process is zero. (C) The entropy is constant for an isentropic process. (D) For an adiabatic system, the entropy of the system cannot decrease. (E) All of the above.
Chemistry
1 answer:
bija089 [108]2 years ago
7 0

Answer:

Option A, C, D

Explanation:

A reversible adiabatic process is an isentropic process as entropy remains constant. Thus,

Entropy change (Delta S) = integral of (Q_rev)/T

Thus, option A and C are correct

For a reversible process, entropy generation is a positive quantity or zero. hence, statement B is not true

In an Adiabatic processes, entropy do not decrease. Hence, option D is also correct

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Carbon disulfide is prepared industrially by reacting carbon with sulfur dioxide according to the above equation. If 70.8 g of c
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Answer:

1.18 moles of CS₂ are produced by the reaction.

Explanation:

We present the reaction:

5C + 2SO₂  →  CS₂  +  4CO

5 moles of carbon react to 2 moles of sulfur dioxide in order to produce 1 mol of carbon disulfide and 4 moles of carbon monoxide.

As we do not have data from the SO₂, we assume this as the excess reagent. We convert the mass of carbon to moles:

70.8 g / 12 g/mol = 5.9 moles

Ratio is 5:1, so 5 moles of carbon react to produce 1 mol of CS₂

Then, 5.9 moles will produce (5.9 . 1) / 5 = 1.18 moles

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Can someone help your amiga :(??
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