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worty [1.4K]
3 years ago
9

Calculate the standard enthalpy of formation of carbon disulfide (CS2) from it's elements, given that C(graphite) + O2(g) → CO2(

g) ΔH o rxn = −393.5 kJ/mol S(rhombic) + O2(g) → SO2(g) ΔH o rxn = −296.4 kJ/mol CS2 + 3O2(g) → CO2(g) + 2SO2(g) ΔH o rxn = −1073.6 kJ/mol
Chemistry
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

Standard enthalpy of formation of Carbon disulfide CS2 = 87.3 KJ/mol

Explanation:

forming CS2 means that it should in the product side

C(graphite) + O2 → CO2                  ΔH = -393.5

2S(rhombic) + 2O2 → 2SO2            ΔH = -296.4 x 2

CO2 + 2SO2 → CS2 + 3O2             ΔH = -1073.6 x -1

the second reaction is multiplied by 2 so that the SO2 and O2 can cancel out.

the third reaction is reversed (multiplied by -1) so that CS2 will be on the product side.

after adding the reaction and cancelling out similarities, the final reaction is: C(graphite) + 2S(rhombic) → CS2

Add ΔH to find the enthalpy of formation of CS2

ΔHf = (-393.5) + (-296.4 x 2) + (-1073.6 x -1) = 87.3 KJ/mol

be aware of signs

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Look at the graph of reaction rate versus substrate concentration for an enzyme. In which region does the reaction rate remain c
OleMash [197]

Answer:

The correct answer is C.

Explanation:

The reaction speed remains constant in region C. This is because the growth rate decreases, tending to zero. Graphically you can see how the slope of the tangent line approaches the horizontal. The slope of the tangent line represents the rate of reaction speed. It is constant because although the concentration continues to increase, the reaction rate does not vary.

Have a nice day!

6 0
4 years ago
What is the kinetic energy of a 25 kg object moving at a velocity of 2.5 m/s?
vovangra [49]

Answer:

<h2>78.13 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 25 \times  {2.5}^{2}  \\  = 12.5 \times 6.25 \\  = 78.125 \:  \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>78.13 J</h3>

Hope this helps you

6 0
3 years ago
A: -3.45<br> B: 17.45 <br> C: 10.55<br> D: 3.55
Minchanka [31]

Answer:

i think its b

Explanation:

6 0
4 years ago
Why do you think the "super-hot" Earth's core is important in this
Lemur [1.5K]

The "super-hot" earth's core is important because it generates the magnetic field around the earth. it also helps control evolution.

7 0
4 years ago
The addition of 0.242 L of 1.92 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions a
kolezko [41]

Answer:

Mass PbCl₂ = 50.24g

Mass AgCl = 14.84g

Explanation:

The addition of Cl⁻ ions from the KCl solution results in the precipitation of AgCl and PbCl₂ as follows:

Ag⁺ + Cl⁻ → AgCl(s)

Pb²⁺ + 2Cl⁻ → PbCl₂(s)

If we define X as mass of PbCl₂, moles of Cl⁻ from PbCl₂ are:

Xg × (1mol PbCl₂/ 278.1g) × (2moles Cl⁻ / 1 mole PbCl₂) = <em>0.00719X moles of Cl⁻ from PbCl₂</em>

<em />

And mass of AgCl will be 65.08g-X. Moles of Cl⁻ from AgCl is:

(65.08g-Xg) × (1mol AgCl/ 143.32g) × (1mole Cl⁻ / 1 mole AgCl) = <em>0.45409 - 0.00698X moles of Cl⁻ from AgCl</em>

<em />

Moles of Cl⁻ that were added in the KCl solution are:

0.242L × (1.92mol KCl / L) × (1mole Cl⁻ / 1 mole KCl) = 0.46464 moles of Cl⁻ added.

<em />

Moles Cl⁻(AgCl) + Moles Cl⁻(PbCl₂) = Moles Cl⁻(added)

0.45409 - 0.00698X moles + (0.00719X moles) = 0.46464 moles

0.45409 + 0.00021X = 0.46464

0.00021X = 0.01055

X = 0.01055 / 0.00021

X = 50.24g

As X = Mass PbCl₂

<h3>Mass PbCl₂ = 50.24g</h3>

And mass of AgCl = 65.08 - 50.24

<h3>Mass AgCl = 14.84g</h3>

6 0
4 years ago
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