Aiko jump roped for 20 minutes before stopping at 8:05. Just count 20 minutes back in order to see when she started.
8:05 - 20 minutes = 7:45
K is 'angle bisector' because it seperated the angle's center.
Hope it helps!
#MissionExam001
Answer:
The larger acute angle is equal to 50.8 degrees.
Step-by-step explanation:
Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.
A = cos^-1 (2√6/2√15)
However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,
A = cos^-1 (2√90/30) = 50.768 degrees.
B = sin^-1 (2√90/30) = 39.231 degrees.
Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.
cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.
If you have any questions on where I got a formula or any step, feel free to ask in the comments!
Answer:
see explanation
Step-by-step explanation:
(1)
(a)
sin(a) = 
= 
(b)
cos(a) = 
= 
(c)
tan(a) = 
= 
----------------------------------------------------
(2)
(a)
sin(b) = =
(b)
cos(b) = =
(c)
tan(b) = = 
