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4 years ago

Choose the correct equation for the line shown on the graph below

Mathematics

1 answer:

Romashka [77]4 years ago

7 0

Step-by-step explanation:

We can write the equation of a straight line as y=mx+b, with m being the slope. We know two points to be (-4,0) and (0,-1) in the (x,y) format. The slope is change in y/change in x, so we can subtract -1 from 0 (-1 is the second y coordinate) and 0 from -4 (0 is the second x coordinate) to get 1/(-4) as our slope. Then, we plug a point in, like (0,-1). We plug that into our formula, y=mx+b. We know that x=0, y=-1, and m(slope)=-1/4, so we can plug that in to get -1=(-1/4)(0)+b, or -1=b. Our equation is then y=(-1/4)x+-1 as our equation should have y and x left open for specific points

You might be interested in

What is the square root of -16?<br> е в<br> -87<br> 0 ООО<br> 8

Monica [59]

$4i$

$i=\sqrt{-1}$

$\sqrt{-16}=\sqrt{-1}*4$

$\sqrt{-16}=i*4$

$4i$

Hope this helps.

頑張って!

8 0

3 years ago

Please actually answer this it has a good amount of points!

Vanyuwa [196]

The answer is D, "No, because two points with the same x-value have different y-values."

Essentially, there cannot be more than one point on the same x-line. Point (2, 11) and point (2, 2) are on the same x-line, which is 2.

Hope this helps!

6 0

3 years ago

Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the

uranmaximum [27]

Part a)

There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.

If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.
If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwords
If there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwords
If there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwords
If there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwords

Adding up those subtotals gives

68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21

different passwords possible.

<h3>Answer: Approximately 9.9207 * 10^21 </h3>

======================================================

Part b)

Let's find the number of passwords where we don't have a special symbol

There are 52+10 = 62 different characters to pick from

If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible.
If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords
If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords
If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords
If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwords

Adding those subtotals gives

62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21

different passwords where we do not have a special character. Subtract this from the answer in part a) above

( 9.9207 * 10^21) - (3.2792 * 10^21) = 6.6415 * 10^21

which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.

<h3>Answer: Approximately 6.6415 * 10^21</h3>

======================================================

Part c)

The answer from part a) was roughly 9.9207 * 10^21

It will take about 9.9207 * 10^21 nanoseconds to try every possible password from part a).

Divide 9.9207 * 10^21 over 1*10^9 to convert to seconds

(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000

This number is 9.9 trillion roughly.

It will take about 9.9 trillion seconds to try every password, if you try a password per second.

------

To convert to hours, divide by 3600 and you should get

(9,920,700,000,000)/3600 = 2,755,750,000

So it will take about 2,755,750,000 hours to try all the passwords.

------

Divide by 24 to convert to days

(2,755,750,000)/24= 114,822,916.666667

which rounds to 114,822,917

So it will take roughly 114,822,917 days to try all the passwords.

------

Then divide that over 365 to convert to years

314,583.334246576

which rounds to 314,583

It will take roughly 314,583 years to try all the passwords

------------------------------

<h3>Answers:</h3>

9.9 trillion seconds
2,755,750,000 hours
114,822,917 days
314,583 years

All values are approximate, and are roughly equivalent to one another.

5 0

3 years ago

Customer arrivals at a bank are random and independent; the probability of an arrival in any one-minute period is the same as th

deff fn [24]

Answer:

a)0.2240

b)0.5768

Step-by-step explanation:

Given:

µ=3

Poison probability is given by :

$f_k=\frac{\mu^ke^-^\mu}{k!}$

a) Evaluating at k=3

$f(3)=\frac{3^3e^-^3}{3!} \approx 0.2240$

b)Evaluating at k=0,1,2:

$f(0)=\frac{3^0e^-^3}{0!} \approx 0.0498$

$f(1)=\frac{3^1e^-^3}{1!} \approx 0.1494$

$f(2)=\frac{3^2e^-^3}{2!} \approx 0.2240$

Use complement rule:

P(x≥3)= 1 - f(0) - f(1) - f(2)= 1- 0.0498 - 0.1494 - 0.2240 =0.5768

4 0

3 years ago

NEED RNN!!!!!

Reptile [31]

Answer: 6.1 and 6.3

Step-by-step explanation: just did it

3 0

3 years ago