Question

Complete the do-while loop to output from 0 to the value of countLimit using printVal. Assume the user will only input a positive number. For example, if countLimit is 5 the output will be:
0
1
2
3
4
5
import java.util.Scanner;
public class CountToLimit {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
int countLimit = 0;
int printVal = 0;
// Get user input
countLimit = scnr.nextInt();
printVal = 0;
do {
System.out.print(printVal + " ");
printVal = printVal + 1;
} while ( /* Your solution goes here */ );
System.out.println("");
return;
}
}

Answer 1

Answer:

Replace

while ( /* Your solution goes here */ );

with

while (printVal <=countLimit );

Explanation:

while (printVal <=countLimit );

This checks if the printVal is less than or equal to countLimit.

While this statement is true, the program will continue printing the required output

See attachment for complete program

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