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zimovet [89]
3 years ago
11

The security administrator of ABC needs to permit Internet traffic in the host 10.0.0.2 and UDP traffic in the host 10.0.0.3. Al

so he needs to permit all FTP traffic to the rest of the network and deny all other traffic. After he applied his ACL configuration in the router nobody can access to the ftp and the permitted hosts cannot access to the Internet. According to the next configuration what is happening in the network? access-list 102 deny tcp any any access-list 104 permit udp host 10.0.0.3 any access-list 110 permit tcp host 10.0.0.2 eq www any access-list 108 permit tcp any eq ftp any
A. The ACL 110 needs to be changed to port 80
B. The ACL for FTP must be before the ACL 110
C. The first ACL is denying all TCP traffic and the other ACLs are being ignored by the router D. The ACL 104 needs to be first because is UDP
Computers and Technology
1 answer:
koban [17]3 years ago
5 0

Answer:

The correct selection is the letter C. The first ACL is denying all TCP traffic and the other ACLs are being ignored by the router.

Explanation:

In this case, the letter C is the right answer because with the first ACL exactly:

access-list 102 deny tcp any any

We are denying all traffic with the next line deny tcp any any, in this case, the others line are being ignored.

access-list 104 permit udp host 10.0.0.3 any

access-list 110 permit tcp host 10.0.0.2 eq www any

access-list 108 permit tcp any eq ftp any

For that nobody can access to the internet, the security administrator of ABC must change the first ACL.

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SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R
Ne4ueva [31]

Answer:

Check the explanation

Explanation:

CODE:-

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

Kindly check the attached image below for the code output.

5 0
3 years ago
The number of pixels displayed on the screen is known as ​
puteri [66]

Answer: Resolution

Explanation: The total number of pixels that can be displayed on the screen at a time is called the resolution of the screen. This resolution is normally described in the pair of numbers, such as 2560 x 1440. This means, the computer screen is 2560 pixels wide and 1440 pixels tall.

4 0
3 years ago
5. Write few lines of code that creates two arrays with malloc. Then write a statement that can create a memory leak. Discuss wh
Darina [25.2K]

Answer:

 // function with memory leak  

void func_to_show_mem_leak()  {  

int *pointer;

pointer = malloc(10 * sizeof(int));

*(pointer+3) = 99;}  

 

// driver code  

int main()  

{  

    // Call the function  

   // to get the memory leak  

   func_to_show_mem_leak();  

     return 0;  }

Explanation:

Memory leakage occurs when programmers allocates memory by using new keyword and forgets to deallocate the memory by using delete() function or delete[] operator. One of the most memory leakage occurs by using wrong delete operator. The delete operator should be used to free a single allocated memory space, whereas the delete [] operator should be used to free an array of data values.

3 0
3 years ago
Subjects with a lot of ___ make focusing easier.
Elden [556K]

Answer:

things is the correct answer

5 0
3 years ago
Read 2 more answers
#Write a function called has_a_vowel. has_a_vowel should have #one parameter, a string. It should return True if the string #has
Vladimir [108]

Answer:

Here is code in java.

import java.util.*;

class Main

{

// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // scanner object to read input from user

       Scanner obj=new Scanner(System.in);

       System.out.println("please enter a string:");

       //read the string input

       String inp=obj.next();

       // call the function to check whether string has vowel or not

       Boolean res=has_a_vowel(inp);

       // printing the result

       System.out.println("string contains vowel."+res);

     

       

   }catch(Exception ex){

       return;}

}

 // method to check string has vowel or not

public static boolean has_a_vowel(String str)

{

 // find length of the string

    int len=str.length();

   

    Boolean flag=false;

     int i;

    for( i=0;i<len;i++)

    {

        char chh=str.charAt(i);

         // if string contains vowel then flag will be true

        if(chh=='a'||chh=='e'||chh=='i'||chh=='o'||chh=='u')

        {

            flag=true;

            break;

        }

    }

     //returning the result

    return flag;

}

}

Explanation:

Create a scanner class object to read the string and assign it to variable

"inp".Call the function "has_a_vowel" with a string parameter.In this function

find the length of string and travers the string.If there is any vowel character

in the string then flag will be set to true otherwise flag will be false. Then it will

return the value of flag.We can test the function from the main by passing a string parameter.

Output:

please enter a string:                                                                                                                                        

vjcavcavacvajjfd                                                                                                                                              

string contains vowel:true

please enter a string:                                                                                                                                        

sdfdhgjkhltyrqwzxcvbmm                                                                                                                                        

string contains vowel: false                                                                                                                                  

                             

8 0
3 years ago
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