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zimovet [89]
3 years ago
11

The security administrator of ABC needs to permit Internet traffic in the host 10.0.0.2 and UDP traffic in the host 10.0.0.3. Al

so he needs to permit all FTP traffic to the rest of the network and deny all other traffic. After he applied his ACL configuration in the router nobody can access to the ftp and the permitted hosts cannot access to the Internet. According to the next configuration what is happening in the network? access-list 102 deny tcp any any access-list 104 permit udp host 10.0.0.3 any access-list 110 permit tcp host 10.0.0.2 eq www any access-list 108 permit tcp any eq ftp any
A. The ACL 110 needs to be changed to port 80
B. The ACL for FTP must be before the ACL 110
C. The first ACL is denying all TCP traffic and the other ACLs are being ignored by the router D. The ACL 104 needs to be first because is UDP
Computers and Technology
1 answer:
koban [17]3 years ago
5 0

Answer:

The correct selection is the letter C. The first ACL is denying all TCP traffic and the other ACLs are being ignored by the router.

Explanation:

In this case, the letter C is the right answer because with the first ACL exactly:

access-list 102 deny tcp any any

We are denying all traffic with the next line deny tcp any any, in this case, the others line are being ignored.

access-list 104 permit udp host 10.0.0.3 any

access-list 110 permit tcp host 10.0.0.2 eq www any

access-list 108 permit tcp any eq ftp any

For that nobody can access to the internet, the security administrator of ABC must change the first ACL.

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Tortise and hare race java g Modify the main class so it runs the race 100 times and reports how many times each runner wins. (T
SOVA2 [1]

Answer:

Game.java file

import java.util.Scanner;

public class Game {

/**

* t_pos and h_pos are the current positions of the Tortoise and Hare

*/

static int t_pos,h_pos;

static Tortoise tortoise;

static Hare hare;

public static void main(String[] args) {

play(); /*starting the game*/

}

public static void play(){

/**

* the method will starts the play, loop until the game is over, displays the winner

* and prompts the user if they want to play again

*/

/**

* defining Tortoise and Hare objects

*/

tortoise=new Tortoise();

hare=new Hare();

t_pos=1;

h_pos=1;

System.out.println("The race is about to start");

tortoise.printTrack();

hare.printTrack();

while(t_pos != 50 && h_pos !=50){

System.out.println("\n\n\n"); /*printing blank lines*/

t_pos=tortoise.move(); /*moving and getting the current position of tortoise*/

h_pos=hare.move();/*moving and getting the current position of hare*/

tortoise.printTrack(); /*displaying the tracks*/

hare.printTrack();

try { /*comment this part to skip the 1s break between each round; for testing*/

Thread.sleep(1000);

} catch (InterruptedException e) {

e.printStackTrace();

}

}

System.out.println("\nRace Over");

if(t_pos==50 && h_pos==50){

System.out.println("Its a tie");

}

else if(t_pos==50){

System.out.println("Tortoise wins");

}else if(h_pos==50){

System.out.println("Hare wins");

}

System.out.println("Do you want to play again? (y/n)");

Scanner scanner=new Scanner(System.in);

String ch=scanner.next();

if(ch.equalsIgnoreCase("y")){

play();

}else if(ch.equalsIgnoreCase("n")){

System.out.println("Thanks for playing, Goodbye");

}else{

System.out.println("Invalid choice, quitting..");

}

}

}

//Tortoise.java

public class Tortoise {

/**

* the current position of the tortoise

*/

int position;

/**

* track array

*/

char[] track;

/**

* speed of tortoise

*/

int speed=1;

public Tortoise() {

position=0;

track=new char[50];

for(int i=0;i<track.length;i++){

/**

* filling the track

*/

track[i]='-';

}

}

public int move(){

if(position<track.length){

position=position+speed;

}

return position+1;

}

public void printTrack(){

/**

* the current position of tortoise will be displayed by 'T' everything else will be '-'

*/

System.out.println();

for(int i=0;i<track.length;i++){

if(i==position){

System.out.print('T');

}else{

System.out.print(track[i]);

}

}

}

}

//Hare.java

import java.util.Random;

public class Hare {

int position;

int speed=10;

char[] track;

/**

* Random object to generate a random number

*/

Random random;

/**

* resting percent denotes how much time Hare will be resting

*/

int resting_percent=90;

public Hare() {

position=0;

track=new char[50];

for(int i=0;i<track.length;i++){

track[i]='-';

}

random=new Random();

}

public int move(){

int n=random.nextInt(100-1)+1; /*generating a random number between 1 and 100*/

if(n<=resting_percent){

/**

* at rest; will not move, returns the current position.

*/

return position;

}else{

/**

* not resting..

*/

if(position<track.length){

if(position+speed>=track.length){

position=track.length-1;

}else{

position=position+speed;

}

}

return position+1;

}

}

public void printTrack(){

System.out.println();

for(int i=0;i<track.length;i++){

if(i==position){

System.out.print('H');

}else{

System.out.print(track[i]);

}

}

}

}

/*Output (partial and random)*/

The race is about to start

T-------------------------------------------------

H-------------------------------------------------

-T------------------------------------------------

H-------------------------------------------------

--T-----------------------------------------------

H-------------------------------------------------

---T----------------------------------------------

----------H---------------------------------------

.

.

.

.

-----------------------------------------------T--

-------------------------------------------------H

Race Over

Hare wins

Do you want to play again? (y/n)

y

The race is about to start

T-------------------------------------------------

H-------------------------------------------------

-T------------------------------------------------

H-------------------------------------------------

.

.

.

.

-----------------------------------------------T--

--------------------H-----------------------------

------------------------------------------------T-

--------------------H-----------------------------

-------------------------------------------------T

--------------------H-----------------------------

Race Over

Tortoise wins

Do you want to play again? (y/n)

n

Explanation:

3 0
3 years ago
Most people entering the construction industry learn a specific craft through:
LuckyWell [14K]
Most people entering the construction industry learn a specific craft through: An apprenticeship program
7 0
3 years ago
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If a piece of software designed to run on Windows XP can run on the latest version of Windows, we say the latest version of Wind
cluponka [151]

Answer:

Forward Compatible

Explanation:

If a piece of software designed to run on Windows XP can run on the latest version of Windows, we say the latest version of Windows is Forward Compatible.

Forward compatibility or upward compatibility is a design characteristic that allows a system to accept input intended for a later version of itself. The concept can be applied to entire systems, electrical interfaces, telecommunication signals, data communication protocols, file formats, and computer programming languages.

The objective for forward compatible technology is for old devices to recognise when data has been generated for new devices.

3 0
3 years ago
Discribe two ways you can zoom in and out from an image
krek1111 [17]

Answer:

Select the Zoom tool, and then do any of the following:

<h2>#1. </h2>

Click and hold in the image to zoom in. Press Alt (Windows) or Option (Mac OS) to zoom out.

<h2>#2!</h2>

In the options bar, select Scrubby Zoom. Then drag to the left in the image to zoom out, or to the right to zoom in.

<h2>psst! pls, brailiest!</h2>
3 0
3 years ago
Read 2 more answers
Implement function hex2dec that takes a hex number hex_num as a string argument and prints out the corresponding decimal number.
DerKrebs [107]

Answer:

Check the explanation

Explanation:

#include <iostream>

using namespace std;

void hex2dec(string hex_num){

int n = 0;

//Loop through all characters in string

for(int i=0;i<hex_num.size();i++){

//take ith character

char c = hex_num[i];

//Check if c is digit

if(c>='0' && c<='9'){

n = 16*n + (c-48);

}

//Convert c to decimal

else{

n = 16*n + (c-55);

}

}

cout<<hex_num<<" : "<<n<<endl;

}

int main()

{

hex2dec("EF10");

hex2dec("AA");

return 0;

}

The Output can be seen below :

4 0
3 years ago
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