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densk [106]
3 years ago
13

On a coordinate plane, a line goes through (0, 3) and (3, negative 1). A point is at (negative 3, 2).

Mathematics
2 answers:
astra-53 [7]3 years ago
5 0

Answer: D: 4x+3y=-6

Step-by-step explanation:

Alex Ar [27]3 years ago
5 0

Answer:

4x + 3y = −6

Step-by-step explanation:

just took the test!

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Most decks of playing cards contain 4 suits - hearts, clubs, diamonds, and spades. If you choose one card from the deck at rando
Murrr4er [49]

Answer:

1/4

Step-by-step explanation:

there are only four suits and an equal number of cards from each suit, which makes 13 hearts, clubs, spades, and diamonds, so the chance for one of them to be chosen is 13/52, which is reduced to 1/4, or 25 percent.

have a good day friend :)

5 0
2 years ago
What is the product,in square of the width (x = 18x) and the height (y) of the prism??
a_sh-v [17]
I think the answer to (Y) may be 40 cubic units
6 0
3 years ago
One year, the population of a city was 333,000. Several years later it was
Sunny_sXe [5.5K]

Answer:12%

Step-by-step explanation:

(333000-293040)×100/333000

7 0
3 years ago
Suppose that 45% of people have dogs. If two people are randomly chosen, what is the probability that they both have a dog
mylen [45]

Answer:

P(Dogs) = 0.2025

Step-by-step explanation:

Given

Proportion, p = 45\%

Required

Probability of two people having dog

First, we have to convert the given parameter to decimal

p = \frac{45}{100}

p = 0.45

Let P(Dogs) represent the required probability;

This is calculated as thus;

<em>P(Dogs) = Probability of first person having a dog * Probability of second person having a dog</em>

<em />

P(Dogs) = p * p

P(Dogs) = 0.45 * 0.45

P(Dogs) = 0.45^2

P(Dogs) = 0.2025

<em>Hence, the probability of 2 people having a dog is </em>P(Dogs) = 0.2025<em />

4 0
3 years ago
Stuck on this problem of my hw. could use some help!​
Mazyrski [523]

Answer:

12 is the answer

Step-by-step explanation:

4 0
3 years ago
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