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Kruka [31]
4 years ago
7

9.4 Lead sheet is pop-riveted with special bronze fasteners. The total exposed area of the sheet is 100 times that of the fasten

ers. The environment for the assembly is seawater. Which metal will corrode? If half as many fasteners are used, what influence would this have on the total rate of corrosion? How could corrosion be reduced?
Engineering
2 answers:
Alinara [238K]4 years ago
7 0

Answer:

(a) Lead will corrode

(b) fasteners does not have any influence on the rate of corrosion.

(c) The use of protective coating like paint, powder

Explanation:

(a) Which metal will corrode: Since bronze is resistant to oxidation, corrosion cannot take place. Lead will corrode due to its reaction with the seawater.

(b) Influence on the total rate of corrosion; No matter the fasteners used, corrosion will still take place as far as the surface of the metal is exposed. therefore fasteners does not have any influence on the rate of corrosion.

(c) there are so many ways to reduce corrosion, some of which includes;

-- The use of protective coating like paint, powder

-- By keeping the surface of the metal dry

-- Not exposing the metal to moisture

---By electroplating it with another metal

joja [24]4 years ago
4 0

Answer:

Questions are answered in the explanation section.

Explanation:

a) Of both metals, lead will corrode, since it reacts with seawater to form oxides, chlorides, etc., while bronze is more resistant to oxidation.

b) The corrosion rate will remain constant, because the concentration of seawater does not change over time, therefore, the corrosion rate is independent of the area that is exposed to seawater.

c) Corrosion can be reduced by using protective coatings, so that the metal is isolated from sea water, for example, paints, acrylic powders, etc.

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Answer:

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3 years ago
Find the mathematical equation for SF distribution and BM diagram for the beam shown in figure 1.​
Novosadov [1.4K]

Answer:

i) SF: v(x) = \frac{(w_0* x )^2}{2L}

ii) BM : = \frac{(w_0*x)^3}{6L}

Explanation:

Let's take,

\frac{y}{w_0} = \frac{x}{L}

Making y the subject of formula, we have :

y = \frac{x}{L} * w_0

For shear force (SF), we have:

This is the area of the diagram.

v(x) = \frac{1}{2} * y = \frac{1}{2} * \frac{x}{L} * w_0

= \frac{(w_0* x )^2}{2L}

The shear force equation =

v(x) = \frac{(w_0* x )^2}{2L}

For bending moment (BM):

BM = v(x) * \frac{x}{3}

= \frac{(w_0* x )^2}{2L}  * \frac{x}{3}

= \frac{(w_0*x)^3}{6L}

The bending moment equation =

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5 0
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In normal operation, a paper mill generates excess steam at 20 bar and 400◦C. It is planned to use this steam as the feed to a t
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Answer:

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Explanation:

Using the steam table

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Mass flow rate of steam = 5000 kg/hr = 5000 kJ/hr × 1 hr/3600 s = 1.389 kg/s

Maximum power generated = change in enthalpy × mass flow rate = 92 kJ/kg × 1.389 kg/s = 127.788 kJ/s = 127.788 kW

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3 years ago
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“How old are the legos” 89 years old.


“Who created them?” Ole Kirk Christiansen.


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Hope this helps•


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•Kate•
4 0
3 years ago
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