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il63 [147K]
3 years ago
8

A structural member that has a straight longitudinal axis and constant cross section is best described as _______.

Engineering
1 answer:
grigory [225]3 years ago
7 0
A structural member that has a straight longitudinal axis and constant cross section is best described as Prismatic/Prismatic bar.
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15. A cold-chamber die-casting machine operates automatically, supported by two industrial robots.The machine produces two zinc
Softa [21]

Answer:

a. 121 Btu/lb

b. 211.8lb

c. 2.69/pc

Explanation:

See the attachments please

4 0
3 years ago
Read 2 more answers
The following is a correlation for the average Nusselt number for natural convection over spherical surface. As can be seen in t
vovikov84 [41]

Answer:

Explanation:

r_2=∞

q=4\pi kT_1(T_2-T_1)\\

q=2\pi kD.ΔT--------(1)

q=hA ΔT=4\pi r_1^2(T_2_s-T_1_s)\\

N_u=\frac{hD}{k} = 2+\frac{0.589 R_a^\frac{1}{4} }{[1+(\frac{0.046}{p_r}\frac{9}{16} )^\frac{4}{9}  }  ------(3)

By equation (1) and (2)

2\pi kD.ΔT=h.4\pi r_1^2ΔT

2kD=hD^2\\\frac{hD}{k} =2\\N_u=\frac{hD}{k}=2\\-------(4)

From equation (3) and (4)

So for sphere R_a→0

6 0
3 years ago
A 50 Ibm block is moving at 4 ft/s. Find Its total kinetic energy? Also find Its kinetic energy per unit mass is
Kamila [148]

Answer:

Total kinetic energy= 400 puondal foot

Kinetic energy per unit mass= 8 (poundaul foot/lb)

Explanation:

To determine the total kinetic energy of the block we use the equation:

Kinetic energy = (1/2) × m × (v^{2}) = (1/2) × (50lb) × (4 foot/s)^{2}) =

= 400 poundal foot

To establish the kinetic energy per unit of mass we must simply divide the value of the total kinetic energy obtained previously by the mass of the block obtaining:

Kinetic energy per unit mass= (400 poundal foot) / (50lb) =

= 8 (poundaul foot/lb)

3 0
3 years ago
A sewer pipe 8 inches in diameter can carry 0.662 ft3/s when flowing at a depth of 4 inches.
Rom4ik [11]

Answer:

a) the flow under full capacity is  q₂= 1.334 ft³/s

b) the velocity would be v= 3.793 ft/s

Explanation:

a) Since the pipe has 8 inches in diameter but 4 are covered with water flow ( half of a circle in area=A₁) , q₁=0.662 ft³/s then

q₁=A₁*v

then for the same velocity v but area A₂=2*A₁

flow under full capacity= q₂ = A₂*v= 2*A₁*v= 2*q₁=2*0.662 ft³/s= 1.334 ft³/s

b) when flowing at a depth of 4 inches

A₁= (1/2)*(π*D²/4) = π* (1/8)*(8 in)² = 8π in² * (1  ft²/ 144  in²) = π/18 ft² = 0.1745 ft²

then

v=q₁/A₁ = 0.662 ft³/s/0.1745 ft²= 3.793 ft/s

v= 3.793 ft/s

6 0
4 years ago
What is the purpose of the graphic language?
solmaris [256]

Answer:

enables the representation, analysis and communication of various aspects of an information system. These aspects correspond to varying and incomplete views of information systems and the processes therein.

5 0
3 years ago
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