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SSSSS [86.1K]
4 years ago
9

A concert hall has three sections: the main floor, the balcony, and the gallery. For a recent concert, 1020 tickets were sold. T

here were twice as many balcony tickets sold as gallery tickets, and 225 more main floor tickets than balcony tickets. If g represents the number of gallery tickets sold, which expressions represents this situation? a. Gallery: g b. Gallery: gg225 Balcony: 9 Balcony: 2g Main Floor: g 225 Main Floor: g c. Gallery: g d. Gallery: g Balcony: g+225 Balcony: 2g Main Floor: 2g+225 Main Floor: 2g 225
Mathematics
2 answers:
Virty [35]4 years ago
8 0

Answer: the expressions that represents this situation is

Gallery: g

Balcony: 2g

Main floor: 2g + 225

Step-by-step explanation:

Let g represent the number of gallery tickets that were sold,

The concert hall has three sections: the main floor, the balcony, and the gallery. There were twice as many balcony tickets sold as gallery tickets. This means that the number of balcony tickets is 2g.

There were 225 more main floor tickets than balcony tickets. This means that the number of main floor tickets that was sold is

2g + 225

The total number of tickets that were sold at the concert is 1020. This is expressed as

g + 2g + 2g + 225 = 1020

kakasveta [241]4 years ago
4 0

Answer:

Gallery: g

Balcony: 2g

Main floor: 2g+225

Step-by-step explanation:

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MrMuchimi

Answer:

<u>4.</u>

Step-by-step explanation:

Degree will he 4, since the largest exponent will still be 4 after the addition.

6 0
2 years ago
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4 years ago
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9. Solve the system of equations using substitution.<br>y = 2x - 10<br>y = 4x - 8​
krok68 [10]
Since they’re both in standard form and they both say that y is equal to something, you just have to set them up with one another
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3 years ago
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I’m not quite sure how to find the median..
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6 0
3 years ago
Can someone please help me with this last one. I am totally lost and don’t understand
Ad libitum [116K]

Answer:

g(-4) = -1

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g(1) = 3

Explanation:

If you are given a function that is defined by a system of equations associated with certain intervals of x, just find which interval makes x true, and then substitute x into the equation of that interval.

For example, given g(-4), this is an expression which is asking for the value of the equation when x = -4. So -4 is not ≥ 2, so ¼x - 1 will not be used. -4 is also not ≤ -1 and ≤ 2, so -(x - 1)² + 3 will not be used either. So in turn, we will just use -1 which is always -1 so g(-4) will just be -1, right because there is no x variable in -1 so it will always be the same.

Using the same idea as before g(-1) is g(x) when x = -1 so -1 will not be a solution because -1 is not less than -1 (< -1). -1 is not ≥ 2 either so we will be using the second equation because -1 is part of the interval -1≤x≤2 (it is a solution to this inequality), therefore -(x - 1)² + 3 will be used.

As x = -1, -(x - 1)² + 3 = -(-1 - 1)² + 3 = -(-2)² + 3 = -4 + 3 = -1.

It is a coincidence that g(-1) = -1.

Now for g(1), where g(x) has an input of 1 or the value of the function where x = 1, we will not use the first equation because x = 1 → x < -1 → 1 < -1 [this is false because 1 is never less than -1], so we will not use -1.

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