The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%.
Answer:
Step-by-step explanation:
here,
a = 1,
b = k
c = 9
now,
Answer:
4y + 48 - 16x = 0 ~Solve for y~
4y = -48 + 16x
y = -12 + 4x
The slope is 4.
We'll use the point (1, 4) and m = 4.
Plug these into the equation: y - y1 = m(x - x1)
y - 4 = 4(x - 1)
y - 4 = 4x - 4
y = 4x
I think the critters ate 5 1/2 packages of Toni’s oatmeal.
If he ate half as much as the others you should total up the others and divide it by 2.
3 + 2 + 6 = 11 11 divided by 2 = 5 1/2
I hope you find this helpful.
Answer:
a₈ = - 1 / 128
Step-by-step explanation:
Given:
First four terms of the sequence
a₁= 1, a₂= - 1/2, a₃= 1/4 and a₄= -1/8
First we recognize that this is a geometric series (sequence) and we must calculate quotient q.
q = a₂/a₁ = a₃/a₂ = (-1/2)/1 = (1/4)/(-1/2) = - 1/2
q = - 1/2
Formula for calculating n-th term is:
aₙ = a₁ · qⁿ⁻¹
According to this:
a₈ = 1 (-1/2)⁷ = - 1/ 128
God with you!!!
