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3 years ago

How do you graph an inequality on a graph?

Mathematics

2 answers:

Kipish [7]3 years ago

5 0

Answer:

1. Rearrange the equation so "y" is on the left and everything else on the right.

2. Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)

3. Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).

Hope this helps UwU

vitfil [10]3 years ago

3 0

Answer:

I'm not sure if I'm right but I believe its right...

Step-by-step explanation:

Graph the inequality as you would a linear equation. Think of: y = 2x + 2 when you create the graph.

Determine which side of the line contains the solutions. Since y is less than the expression, you will shade below the line.

Substitute (0,0) into the inequality y < 2x + 2 0 < 2 (0) + 2 0 < 2 This is a TRUE statement.

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1 2/3 + 3 1/2= ?? <br> 1 and 2 3rds plus 3 and 1 half equals what??

Sunny_sXe [5.5K]

Answer:

5 1/6

Step-by-step explanation:

First you want to get the same denominator on both of the fractions. So you would multiply 1 2/3 or you can change it into a improper fraction which is a fraction greater than 1. So that would be 5/3 times 2/2. Because you want to get the same denominator. That is 10/6. Then you make 3 1/2 a improper fraction which is 7/2 and multiply it by 3/3 to get 21/6. Next you would add them together and get 31/6 but you have to simplify, so you would divide 31 by 6 and get 5 1/6.

I know that's a lot but I hope it helps.

5 0

3 years ago

HELP ASAP PLS!!!

nirvana33 [79]

Answer:

176 seconds

Step-by-step explanation:

By using regression line calculator,

Equation of the line of best fit will be,

T = -12.55x + 276.52

Here , T = time taken to cover one lap

x = Age

If the age of Marsha's son is 8 years then expected time taken by her son to cover one lap will be,

T = -12.55(8) + 276.52

T = -100.4 + 276.52

T = 176.12 seconds

Therefore, approximate time taken by Marta's son will be 176 seconds.

4 0

3 years ago

Gretta is 1 1/2 meters tall. Which of the following is equivalent to 1 1/2 meters? A 150 millimeters B 1.500 millimeters C 100 m

Crazy boy [7]

Answer:

1500 millimeters is your answer

5 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

agasfer [191]

Answer:

rectangle

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago