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solong [7]
3 years ago
7

there are 1200 students at roosevelt middle school there are 700 boys at the school what percentage of the students at roosevelt

are boys
Mathematics
1 answer:
jeyben [28]3 years ago
5 0

The correct answer is 58.33%


(700*100)/1200=58.3333333333

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A circle has An area of 36 pi square inches which best represents the circumference of the circle.
kkurt [141]

Answer: 12πins.

Step-by-step explanation:

Since the area if a circle = πr²

From the question

Area of the circle = 36πins²

To find the circumference of the circle, we need to find the common radius of the circle and this could be achieved from the area of the circle given above.

πr² = 36π, solving this gives. Divide through by π

r² = 36

r = +/-√36

= +/-6

Now to find the circumference of the circle, we substitute for r in the formula below.

Circumstances = 2πr

= 2 ×π × 6

= 12πins.

4 0
2 years ago
The leading brand of cosmetics in the US had about 20% of the total sales in the industry. The total sales were $ 200,000. What
Elanso [62]

Answer: $40000

Step-by-step explanation:

200000(0.2) = $40000

8 0
2 years ago
4. ADEF is an equilateral triangle.<br> E<br> 24<br> 20<br> D<br> F
irinina [24]

By Pythagorean theorem

x²+GF²=EF² ( where G is the point of intersection of perpendicular lines)

now, GF=1/2 EF= 12

x²+12²=24²

x²=24²-12²

x²=432

x=√432

x=12√3

x≈20.78

7 0
2 years ago
From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th
wel

Answer:

\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}

Step-by-step explanation:

The <u>width</u> of a square is its <u>side length</u>.

The <u>width</u> of a circle is its <u>diameter</u>.

Therefore, the largest possible circle that can be cut out from a square is a circle whose <u>diameter</u> is <u>equal in length</u> to the <u>side length</u> of the square.

<u>Formulas</u>

\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}

\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}

\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}

If the diameter is equal to the side length of the square, then:
\implies \sf r=\dfrac{1}{2}s

Therefore:

\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}

So the ratio of the area of the circle to the original square is:

\begin{aligned}\textsf{area of circle} & :\textsf{area of square}\\\sf \dfrac{1}{4}\pi s^2 & : \sf s^2\\\sf \dfrac{1}{4}\pi & : 1\end{aligned}

Given:

  • side length (s) = 6 in
  • radius (r) = 6 ÷ 2 = 3 in

\implies \sf \textsf{Area of square}=6^2=36\:in^2

\implies \sf \textsf{Area of circle}=\pi \cdot 3^2=28\:in^2\:\:(nearest\:whole\:number)

Ratio of circle to square:

\implies \dfrac{28}{36}=\dfrac{7}{9}

5 0
1 year ago
A T-shirt launcher can launch 105 shirts in 20 minutes. What is the rate in shirts per hour?
Margarita [4]

The T-shirt launcher can launch 315 shirts per hour.

4 0
3 years ago
Read 2 more answers
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