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3 years ago

7(2c−5d)−3(d−2c) What’s this answer

Mathematics

1 answer:

Kazeer [188]3 years ago

4 0

1. 7(2c-5d)-3(d-2c)
2. 14c-35d-3d+6c (DISTRIBUTE)
3. Answer: 20c-38d (PUT TOGETHER LIKE TERMS AND SOLVE)

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Hi, Could anyone help me with my homework

tatiyna

Answer:

$\hookrightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

solving steps:

$\rightarrow \sf (x + 4)^6$

$\bold{rewrite \ the \ following}$

$\rightarrow \sf (x + 4)^2 (x + 4)^2 (x + 4)^2$

$\bold {formula \ used : \sf (x+a)^2 = (x^2 + 2xa + a^2)}$

$\rightarrow \sf (x^2 + 8x+16) (x^2 + 8x+16) (x^2 + 8x+16)$

$\bold{simplify \ by \ removing \ parenthesis}$

$\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)$

$\bold{basic \ addition \ of \ integers }$

$\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)$

$\bold{remove \ parenthesis}$

$\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)$

$\bold {final \ answer:}$

$\rightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

8 0

1 year ago

Plz help long division those 4

expeople1 [14]

I would tell you how to do it but its a very hard thing to explain

6 0

2 years ago

Read 2 more answers

Solve for x. 21x + 11 - 5 = 5

Reil [10]

Answer:

x= -1/21

Step-by-step explanation:

21x + 11 - 5 = 5

21x + 6 = 5

(-6 each side)

21x = -1

(divide 21 each side)

x= -1/21

3 0

2 years ago

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How is the graph of the parent quadratic function transformed to produce the graph of y=-(2x+6)? +3?

Aleonysh [2.5K]

Answer:

Step-by-step explanation:

5 0

3 years ago

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A tablet data provider offers different plans for data usage. The plan Raul chose has a monthly fee of $29.99 per month for 5 GB

jeka57 [31]

Answer:

The minimum number is 9 GB to make the unlimited cheaper

Step-by-step explanation:

* Lets explain how to solve the problem

- A tablet data provider offers different plans for data usage

- The plan Raul chose has a monthly fee of $29.99 per month for

5 GB of data with an additional cost of $10 for each gigabyte

over 5

* Assume that he will use n gigabyte per month

∵ The monthly fee is $29.99 for 5 GB

∵ The cost per GB after the first 5 GB is $10

∵ The number of GB whose cost is $10 is (n - 5)

∴ His monthly fees = 29.99 + 10 (n - 5) ⇒ current plan

- Raul learns that his data provider is offering an unlimited data

plan for $59.99 per month

∵ The fees of the unlimited is $59.99 per month

∵ We need the unlimited cheaper than current plane

- Let the current plan greater than the unlimited plan

∴ 29.99 + 10 (n - 5) > 59.99

- Subtract both sides by 29.99

∴ 10 (n - 5) > 30

- Divide both sides by 30

∴ n - 5 > 3

- Add both sides by 5

∴ n > 8

∴ The minimum number is 9 GB to make the unlimited cheaper

6 0

2 years ago