Answer:
area of the trapezoid=1/2(7+12)×5
=47.5cm
Answer: 44
Step-by-step explanation:
we will find RN and NQ, then add together to give us RQ.
To find RN;
RP= 17 PN = 15 and RN =?
using pythagoras theorem,
adj^2 = hyp^2 - opp^2
RN^2 = RP^2 - PN^2
?^2 = 17^2 - 15^2
?^2 = 17^2 - 15^2
?^2 = 289 - 225
?^2 = 64
? = √64
? = 8
RN=8
To find NQ,
PN = 15 PQ=39 and NQ=?
using pythagoras theorem
NQ^2 = PQ^2 - PN^2
?^2 = 39^2 - 15^2
?^2 = 1521 - 225
?^2 = 1296
? = √1296
? = 36
NQ= 36
RQ = RN + NQ
RQ= 8 + 36
RQ=44
The number is 4. 15-6=8 divide that by 2 and you are left with 4
Answer:
Her new monthly payment is now $1,378.91¢
Step-by-step explanation:
For us to calculate the new monthly mortgage payment that Anna will start paying from now on, we need to input the formula for calculating monthly mortgage payments.
The formula is:-
![M = P [\frac{r(1+r)^{n} }{(1+r)^{n}-1}]](https://tex.z-dn.net/?f=M%20%3D%20P%20%5B%5Cfrac%7Br%281%2Br%29%5E%7Bn%7D%20%7D%7B%281%2Br%29%5E%7Bn%7D-1%7D%5D)
Where M is the monthly mortgage payment.
P is the principal
r is the monthly interest rate calculated by dividing your annual interest rate by 12
n is the number of payments(the number of months you will be paying the loan).
In this case, the new principal that Anna must pay back is $231,905.47¢. The annual interest rate has been reduced to 5.17% from 5.75% so the new monthly interest rate will be obtained by dividing the new annual interest rate by 12
= 5.17%/2
= 0.431%
This is the new monthly interest rate.
Since she has been paying her mortgage loan diligently for 5 complete years. It means she now has just 25 years to complete the payment. If 12 months make up one year, then there are - 12 × 25 = 300 more months to go.
300 is therefore "n" that is required for the calculation.
All the terms needed for the calculation of her new monthly mortgage is now complete.
P = $231,905.47¢
r = 0.431%
n = 300
![M = 231,905.47[\frac{0.00431(1+0.00431)^{300} }{(1+0.00431)^{300} -1}]](https://tex.z-dn.net/?f=M%20%3D%20231%2C905.47%5B%5Cfrac%7B0.00431%281%2B0.00431%29%5E%7B300%7D%20%7D%7B%281%2B0.00431%29%5E%7B300%7D%20-1%7D%5D)
![= 231,905.47[\frac{0.00431(3.634)}{2.634}]](https://tex.z-dn.net/?f=%3D%20231%2C905.47%5B%5Cfrac%7B0.00431%283.634%29%7D%7B2.634%7D%5D)
= 231,905.47 × 0.005946
M = $1,378.91¢
Therefore her new monthly mortgage payment will become $1,378.91¢
Hello there! An example problem for this could be:
Emile is looking for a cell-phone plan. His two options are one that costs $40 up front, and costs $0.01 per text, represented by x. The second one is 15 dollars up front and costs $0.06 for each text message. Emile figures that for the first package he has to send 500 texts or more to make it less than the second one.