This is a cube root, so we look for factors of 162 which are perfect cubes.
Find the prime factors of 162:-
162 = 2 * 3 * 3 * 3* 3
27 = 3^3 is a perfect cube
162 = 6 * 27
so ^3√ 162 = ^3√6 * ^3√27 = ^3√6 * 3
so the simplest form is 3 ^3√6
8 1/2=17/2=8.5
24,700 divided by 8.5=2,905,8823
OR
24,700:17/2 =24,700x2/17=2,905,8823
Answer:
The data is skewed, and the lowest number of crackers in a package was 7
Step-by-step explanation:
Hi,
First of all, since the question was incomplete due to the missing capture of the range shown on the box plot. I attached it for you so I could answer your question as well.
Taking into consideration the attached image's information, symmetric would be right down the middle, but it is not.
The image shows that it is <em>positively skewed with the lowest number being 7.</em>