SOMEBODY HELP ME PLEASE

1 answer:

3 0

$4) \: {x}^{2} + 11x + 28 = 0 \\ \Leftrightarrow {x}^{2} + 7x + 4x + 28 = 0 \\ \Leftrightarrow x(x + 7) + 4(x + 7) = 0 \\ \Leftrightarrow (x + 4)(x + 7) = 0 \\\Leftrightarrow x = - 4 \: \vee \: x = - 7 \\ \\ 5) \: (3a + 8)(3 {a}^{2} - a - 7) \\ = 9 {a}^{3} - 3 {a}^{2} - 21a + 24 {a}^{2} - 8a - 56 \\ = 9 {a}^{3} + 21 {a}^{2} - 29a - 56$

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Please hurry I’m in a timed test!!!! If sintheta>0, and tan theta<0 then:

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Evaluate this expression for a = 3 and b = 4.

ahrayia [7]

Answer:

Step-by-step explanation:

a = 3

b = 4

$b(a + 4)-3(3 + 2)+3 - 2\\a = 3,b=4\\4(3+4)-3(5)+3 - 2\\4(7)-15+3 - 2\\28-14\\\\14$