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4 years ago

How can you simplify 18/30?

Mathematics

2 answers:

coldgirl [10]4 years ago

5 0

Answer:

3/5

Step-by-step explanation:

Think: What's the greatest common factor of 18 and 30? It's 6.

Starting with 18/30, divide both numerator and denominator by 6, obtaining:

3/5

Kamila [148]4 years ago

5 0

Answer:

Simplified it would be 3/5

Step-by-step explanation:

Start by dividing them by any common factor that they both have. Both are divisible by 3, so we divide both numbers by 3.

18/3 = 6

30/3 = 10

6/10

At this point, both numbers are still divisible by 2, so we divide them again.

6/2 = 3

10/2 = 5

3/5

Since these numbers share no factors, we know we are done.

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State the postulate or theorem you would use to prove each pair of triangles congruent.

Diano4ka-milaya [45]

Answer:

f) Not possible

Step-by-step explanation:

The triangles can be shown to be similar by SAS, but the corresponding sides are not marked as congruent. With the given information, it is not possible to show the triangles are congruent.

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3 years ago

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

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3 years ago

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Rasek [7]

Hello :
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