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3 years ago

How can you simplify 18/30?

Mathematics

2 answers:

coldgirl [10]3 years ago

5 0

Answer:

3/5

Step-by-step explanation:

Think: What's the greatest common factor of 18 and 30? It's 6.

Starting with 18/30, divide both numerator and denominator by 6, obtaining:

3/5

Kamila [148]3 years ago

5 0

Answer:

Simplified it would be 3/5

Step-by-step explanation:

Start by dividing them by any common factor that they both have. Both are divisible by 3, so we divide both numbers by 3.

18/3 = 6

30/3 = 10

6/10

At this point, both numbers are still divisible by 2, so we divide them again.

6/2 = 3

10/2 = 5

3/5

Since these numbers share no factors, we know we are done.

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What’s the measure of X in this short answers are fine

miv72 [106K]

Answer:

28 = x

Step-by-step explanation:

62 = angle BAC since they are vertical angles

angle ABC is a right angle since KL is perpendicular to FG

Adding the angles in triangle ABC

BAC + ABC + BCA = 180

62 + 90 + BCA = 180

152 + BCA = 180

BCA = 180-152

BCA = 28

BCA = x since they are vertical angles

28 = x

3 0

3 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$