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ahrayia [7]
3 years ago
12

If an object is in uniform circular motion, then it is accelerating towards the center of the circle; yet the object never gets

any closer to the center of the circle. It maintains a circular path at a constant radius from the circle's center. Suggest a reason as to how this can be. How can an object accelerate towards the center without ever getting any closer to the center?
Physics
1 answer:
enot [183]3 years ago
8 0

Answer:

Explanation:

When an object moves in a circle with constant velocity, acceleration is experienced by the object towards the center of the circle. It is due to the change in the direction of the velocity vector which is generating the centripetal acceleration. Thus it the acceleration which velocity is generating itself, so it is not able to move body inwards.

Also, inertia and tangential velocity cause the body to move in the circular path.

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Answer:

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Researchers want to see if college students are more committed to their fraternity after going through a hazardous hazing ritual
Mila [183]

Answer:

College student's commitment

Explanation:

The dependent variable is  the college students since it  is the variable we are going to measure as a result of the independent variable which is  the hazardous hazing ritual or non-hazardous hazing ritual.

8 0
3 years ago
An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at +44 ft/s2. After some time t1,
mash [69]

Answer:

a) t₁ = 4.76 s, t₂ = 85.2 s

b) v = 209 ft/s

Explanation:

Constant acceleration equations:

x = x₀ + v₀ t + ½ at²

v = at + v₀

where x is final position,

x₀ is initial position,

v₀ is initial velocity,

a is acceleration,

and t is time.

When the engine is on and the sled is accelerating:

x₀ = 0 ft

v₀ = 0 ft/s

a = 44 ft/s²

t = t₁

So:

x = 22 t₁²

v = 44 t₁

When the engine is off and the sled is coasting:

x = 18350 ft

x₀ = 22 t₁²

v₀ = 44 t₁

a = 0 ft/s²

t = t₂

So:

18350 = 22 t₁² + (44 t₁) t₂

Given that t₁ + t₂ = 90:

18350 = 22 t₁² + (44 t₁) (90 − t₁)

Now we can solve for t₁:

18350 = 22 t₁² + 3960 t₁ − 44 t₁²

18350 = 3960 t₁ − 22 t₁²

9175 = 1980 t₁ − 11 t₁²

11 t₁² − 1980 t₁ + 9175 = 0

Using quadratic formula:

t₁ = [ 1980 ± √(1980² - 4(11)(9175)) ] / 22

t₁ = 4.76, 175

Since t₁ can't be greater than 90, t₁ = 4.76 s.

Therefore, t₂ = 85.2 s.

And v = 44 t₁ = 209 ft/s.

3 0
3 years ago
the force that is exerted when a shopping cart is pushed. the forces that causes a metal ball to move toward a magnet
alexandr402 [8]

Answer:

The force that is exerted when a shopping cart is pushed is a type of push force, supplied by the muscles of the cart pusher's body.

The forces that causes a metal ball to move toward a magnet is a type of pull force that is as a result of the magnetic field forces.

Explanation:

Forces are divided into push forces that tends to accelerate a body away from the source of the force, and pull forces that accelerates the body towards the force source.

Examples of push forces includes pushing a cart, pushing a table, repulsion of two similar poles of a magnet etc. Examples of pull forces includes a attractive force between two dissimilar poles of a magnet, pulling a load by a rope, a dog pulling on a leash etc.

8 0
3 years ago
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A wave can be described as?
aleksley [76]

Answer:

<em>B) The disturbance of particles in an area.</em>

Explanation:

<em>A wave involves transmission of  energy from one place to another by the actual disturbance of the particles of the medium.</em>

<em />

6 0
3 years ago
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