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3 years ago

A list of heat transfer examples are listed below. Which is NOT an example of convection?

Physics

1 answer:

Alex777 [14]3 years ago

7 0

Answer:

C. Hot pavement burning your feet

Explanation:

Convection is a type of process where heat travels upwards and cold travels downwards.

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What is the value of the charge that experiences a force of 2.4 Ã— 10â€“3 n in an electric field of 6.8 Ã— 10â€“5 n/c?

tia_tia [17]

Answer:

The value of charge is 35.3 C

Explanation:

Given:

Force $F = 2.4 \times 10^{-3}$ N

Electric field $E = 6.8 \times 10^{-5} \frac{N}{C}$

According coulomb's law,

$F = qE$

Where $q =$ charge that experience a force,

For finding the value of charge,

$q = \frac{F}{E}$

$q = \frac{2.4 \times 10^{-3} }{6.8 \times 10^{-5} }$

$q = 35.3$ C

Therefore, the value of charge is 35.3 C

6 0

3 years ago

A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of

andrew11 [14]

Answer:

$\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Explanation:

Knowing that the volume of a sphere is V=(4/3)πr³ and $\frac{dr}{dt}=-0.1\frac{cm}{min}$

We must find $\frac{dV}{dt}=?$ when r=14cm

V=(4/3)πr³ ⇒

$\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})$

and r=14cm then

$\frac{dV}{dt}=4\pi(14cm)^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=4\pi196cm^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}$

Note: as you can see the relationship of change of r with respect to t is negative because it is a decrease, and also its volume ratio

4 0

4 years ago

What force is affected when the distance between two objects remains the same and the mass of each object is doubled?.

rusak2 [61]

Answer:

Gravitational force between masses there is Gravitational force .

3 0

3 years ago

A soda has a volume of 560 mL and a density of 3.2 g/mL. What is the mass?

kolbaska11 [484]

The correct answer is: 1792g or 1800g.

(When you round it)

8 0

4 years ago

What will happen to the centripetal acceleration if the velocity of the object increases to two times its original value?

mrs_skeptik [129]

Answer:

<em>the centripetal acceleration will now be four times its initial value</em>

Explanation:

v=velocity

a=centripetal acceleration

r=radius to the center

take note tat a centripetal force is the force tat is needed to keep a body moving along a circular path

centripetal force is given by f=mv^2/r

a=v^2/r

v=v $v_{0}$

wen v $v_{0}$ is doubled , we ave

2v $v_{0}$

substituting into the previous equation of centripetal force

a=( $(2v_{0})^{2}$ /r

a=4 $v_{0}$ ^{2}/(r)

from the equation, is can be discovered that the centripetal acceleration will now be four times its initial value

4 0

4 years ago