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Diano4ka-milaya [45]
2 years ago
9

Z =-19+3.14i what are the real and imaginary parts of z

Mathematics
1 answer:
Rom4ik [11]2 years ago
7 0

Answer:

gyuuiwhyggwftywgyuwgyugwyuwsyw7y7y

vtsftgygtwfsygyqgy

Step-by-step explanation:

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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 12 feet and
Karolina [17]

Answer:

Step-by-step explanation:

Container A = 75.36 x 17 = 1,281.12

Container B = 62.8 x 18 = 1,130.4

1,281.12 - 1,130.4 = 150.72 is left in container A.

So, 1,130.4 was taken out of it.

1,281.12 divided by 1,130.4 = 1.13

move the decimal over two to the right. Or times it by 100.

113%

5 0
2 years ago
F(x) = 3x + 6. Find the inverse of f(x).
Levart [38]

Answer:

\tt C) \:\tt f^{-1}(x)=\cfrac{x-6}{3}

Step-by-step explanation:

We're given,

\tt f(x) = 3x + 6

~

\tt y=3x+6

\tt x=3y+6

\tt x-6=3y

\tt y=\cfrac{x-6}{3}

\tt f^{-1}(x)=\cfrac{x-6}{3}

~

3 0
2 years ago
What is the balance after 15 years in a savings account that earns 2% interest compounded bimonthly when the initial deposit is
motikmotik

The amount will be equal to $1348.07. The correct option is A.

<h3>What is compound interest?</h3>

Compound interest is the interest levied on the interest. The formula for the calculation of compound interest is given as:-

\rm A = P(1+\dfrac{r}{n})^{nt}

Compound Interest Formula:

A = Account Balance

P = Principle/Initial Amount

r = Rate of Interest (decimal)

n = Number of times compounded (per year)

t = Number of Years

Given Information

Account Balance = ?

It is given that the balance after 15 years in a savings account earns 2% interest compounded bi-monthly when the initial deposit is 1000.

This is because we are gaining money, so the multiplier should be greater than 1. We already added 1, which is 100% so you simply add the 0.02 for the extra 2%.

Number of times compounded per year = 6

This is because it is being compounded bi-monthly, or once every 2 months. 12 months divided by 2 months is 6 months, so 6 times a year.

Number of years = 15

Solve by plugging the given values into the formula.

\rm A = P(1+\dfrac{r}{n})^{nt}

\rm A = 1000(1+\dfrac{0.02}{6})^{6 \times 15}

A = 1000 x (1.14)

A = $1348.07.

Therefore, the amount will be equal to $1348.07. The correct option is A.

To know more about Compound interest follow

brainly.com/question/24924853

#SPJ1

3 0
1 year ago
1) work out the value of (1.7x10^4)x (8.5x10^-2) give your answer in standard form.
Mashutka [201]

ANSWER TO QUESTION 1

(1.7\times 10^4)\times(8.5\times 10^{-2})


We rewrite to obtain;


(1.7\times 10^4)\times(8.5\times 10^{-2})=(1.7\times 8.5)\times(10^4\times 10^{-2})


Recall this product law of indices


a^m\times a^n=a^{m+n}


we apply this law to obtain,


(1.7\times 10^4)\times(8.5\times 10^{-2})=14.45\times10^{4+-2}



This simplifies to


(1.7\times 10^4)\times(8.5\times 10^{-2})=14.45\times10^{2}


We need to rewrite this in standard form;


(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^1\times10^{2}


We apply the product law again to get


(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^{1+2}


This simplifies to

(1.7\times 10^4)\times(8.5\times 10^{-2})=1.445\times 10^{3}



ANSWER TO QUESTION 2


(6.8\times 10^2)\times(1.3\times 10^{-3})


We rewrite to obtain;


(6.8\times 10^2)\times(1.3\times 10^-3)=(6.8\times 1.3)\times(10^2\times 10^{-3})


Recall this product law of indices


a^m\times a^n=a^{m+n}


we apply this law to obtain,


(6.8\times 10^2)\times(1.3\times 10^-3)=8.84\times10^{2+-3}



This simplifies to


(6.8\times 10^2)\times(1.3\times 10^-3)=8.84\times10^{-1}


This is already in standard form.







8 0
3 years ago
F(x)=2(x+2)²-1 determine the vertex (h,k)
bazaltina [42]
The vertex would be, (-2,-1)
6 0
2 years ago
Read 2 more answers
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