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dmitriy555 [2]
3 years ago
11

Which planet formed near the Sun where the solar system’s temperatures were very highWhich planet formed near the Sun where the

solar system’s temperatures were very high?
Physics
2 answers:
NeX [460]3 years ago
5 0

Answer:

Venus

Explanation:

The terrestrial planets are the planets in the solar system which are closer to the Sun, compared to the Gaseous giants like Jupiter.

Venus is the planet that is near the Sun and is formed where the solar system's temperatures are very high.

Mercury is the planet  which has a very thin atmosphere and so is very cold. Venus is a planet similar to Earth, but it has a dense atmosphere . So venus is hottest compared to other  planets.

tankabanditka [31]3 years ago
4 0

Answer:

I think it is Mars or B

Explanation:

Hope all is well!

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You set out to design a car that uses the energy stored in a flywheel consisting of a uniform 101-kg cylinder of radius r that h
Ket [755]
Ok, assuming "mj" in the question is Megajoules MJ) you need a total amount of rotational kinetic energy in the fly wheel at the beginning of the trip that equals
(2.4e6 J/km)x(300 km)=7.2e8 J
The expression for rotational kinetic energy is

E = (1/2)Iω²  

where I is the moment of inertia of the fly wheel and ω is the angular velocity.  
So this comes down to finding the value of I that gives the required energy.  We know the mass is 101kg.  The formula for a solid cylinder's moment of inertia is

 I = (1/2)mR²

We want (1/2)Iω² = 7.2e8 J and we know ω is limited to 470 revs/sec.  However, ω must be in radians per second so multiply it by 2π to get 
ω = 2953.1 rad/s
Now let's use this to solve the energy equation, E = (1/2)Iω²,  for I:
I = 2(7.2e8 J)/(2953.1 rad/s)² = 165.12 kg·m²

Now find the radius R,

 165.12 kg·m² = (1/2)(101)R²,
√(2·165/101) = 1.807m

R = 1.807m
8 0
3 years ago
What is the equation for electric potential
Rama09 [41]

Answer:

The unit of charge is the Coulomb (C), and the unit of electric potential is the Volt (V), which is equal to a Joule per Coulomb (J/C).

Explanation:

4 0
3 years ago
Which magnetic property best describes a magnet’s ability to act at a distance?
blsea [12.9K]
Magnetic field describea magnet's ability to act at a distance

8 0
4 years ago
Read 2 more answers
How long does it take light from a camera to travel to the face of someone standing 7 meters away?
mestny [16]

The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:

<h3>Speed = distance / time </h3>

With the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:

Distance = 7 m

Speed of light = 3×10⁸ m/s

<h3>Time =?</h3>

Time = Distance / speed

Time = 7 / 3×10⁸

<h3>Time = 2.33×10¯⁸ s</h3>

Therefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s

Learn more: brainly.com/question/14988345

8 0
2 years ago
If a transmission line in a cold climate collects ice, the increased diameter tends to cause vortex formation in a passing wind.
AleksAgata [21]

Answer:

a) f_1=5.587Hz

b) f_{n+1}-f_n=5.587Hz

Explanation:

The frequency of the n^{th} harmonic of a vibrating string of length <em>L, </em>linear density \mu under a tension <em>T</em> is given by the formula:

f_n=\frac{n}{2L} \sqrt{\frac{T}{\mu}

a) So for the <em>fundamental mode</em> (n=1) we have, substituting our values:

f_1=\frac{1}{2(347m)} \sqrt{\frac{65.4\times10^6N}{4.35kg/m}}=5.587Hz

b) The <em>frequency difference</em> between successive modes is the fundamental frequency, since:

f_{n+1}-f_n=\frac{n+1}{2L} \sqrt{\frac{T}{\mu}}-\frac{n}{2L} \sqrt{\frac{T}{\mu}}=(n+1-n)\frac{1}{2L} \sqrt{\frac{T}{\mu}}=\frac{n}{2L} \sqrt{\frac{T}{\mu}}=f_1=5.587Hz

3 0
3 years ago
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