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Jlenok [28]
3 years ago
15

What would happen if you use a thicker wire around the iron nail of an electromagnet? (thats the whole question)

Physics
1 answer:
puteri [66]3 years ago
3 0

Answer:

When we have a current I, we will have a magnetic field perpendicular to this current.

Then if we have a wire in a "spring" form. then we will have a magnetic field along the center of this "spring".

Now suppose we put an iron object in the middle (where the magnetic field is) then we will magnetize the iron object.

Of course, the intensity of the magnetic field is proportional to the current, given by:

B = (μ*I)/(2*π*r)

Where:

μ is a constant, I is the current and r is the distance between to the current.

Now remember that for a resistor:

R = ρ*L/A

R is the resistance, ρ is the resistivity, which depends on the material of the wire, L is the length of the wire, and A is the cross-section of the wire.

If we increase the area of the wire (if we use a thicker wire).

And the relation between resistance and current is:

I = V/R

Where V is the voltaje.

Now, if we use a thicker wire, then the cross-section area of the wire increases.

Notice in the resistance equation, that the cross-section area is on the denominator, then if we increase the area A, the resistance decreases.

And the resistance is on the denominator of the current equation, then if we decrease R, the current increases.

If the current increases, the magnetic field increases, which means that we will have a stronger electromagnet.

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A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the
VLD [36.1K]

Answer:

0.75 NC⁻¹

Explanation:

Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,

So, Force (F) = Electric field intensity(E) × Charge (q)

                 F = E×q ⇒ q = F/E

                                      = 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹

According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted  on both charges.

According to cool om's law,

F =G×q1×q2 / r²

F = force exerted of two charges

q1 , q2 = charges

r = distance between two charges

And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge

6 0
3 years ago
Read 2 more answers
this is my 5th time waisting my points for this question because I could fail my final and I am not getting any answers so can s
Neko [114]

Answer:

<em>The person needs to apply 25 N to balance the seesaw</em>

Explanation:

<u>Moment</u>

The moment of a force is a measure of its tendency to cause a body to rotate about a specific point or axis.

The moment M of a force F located at a distance x from the axis of rotation is calculated as follows:

M = F.x

The image shows a moment of M=100 N.m is needed to be applied to balance the seesaw. It can also be noted that the distance to the pivot is x=4 m

To calculate the force needed to balance the seesaw, we solve for F:

\displaystyle F=\frac{M}{x}

\displaystyle F=\frac{100\ N.m}{4\ m}

F = 25 N

The person needs to apply 25 N to balance the seesaw

8 0
3 years ago
How does natural selection produce change in a population of mice?
sergey [27]

Answer:

The population of the mice will decrease to the faster, stronger, and smarter mice because the weaker will die because of natural selection.

Explanation:

5 0
3 years ago
Determine the gravitational field 300km above the surface of the earth. How does this compare to the field on the earth's surfac
Serjik [45]
The strength of the gravitational field is given by:
g= \frac{GM}{r^2}
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.

In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m

And now we can use the previous equation to calculate the field strength at that altitude:
g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2}  = 8.95 m/s^2

And we can see this value is a bit less than the gravitational strength at the surface, which is g_s = 9.81 m/s^2.
4 0
3 years ago
What is the difference between scientific law and scientific theory
Vedmedyk [2.9K]

Answer:

In general, a scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory.

Explanation:

8 0
3 years ago
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