|V| = 10.33 units and the direction θ = -47.35° or 312.65°.
Given the x and y components of a vector, we can calculate the magnitude and direction from these components.
Applying the Pythagorean theorem we have that the magnitude of the vector is:
|V| = 
|V| = 
The expression for the direction of a vector comes from the definition of the tangent of an angle:
tan θ = 
------> θ = arc tan
θ = arc tan 
θ = -47.35° or 312.65°
To find how far east we drove (This is the displacement), we simple subtract 12 from 40.
An easy way to do this in your head is to round 12 down to 10, subtract 10 from 40, then subtract the remaining 2. This should result in an answer showing that you drove 28 miles east.
true ........i really dont kno but ok hope this helps
Answer:
B = 4.323 T
Explanation:
We are given;
Inner radius; r_i = 0.7 m
Number of turns; N = 890 turns
Current; I = 17 KA = 17000 A
Formula for the magnetic field inside the toroid along the inner radius is given by;
B = (μ_o × N × I)/(2πr)
μ_o is vacuum of permeability with a constant value of 4π × 10^(-7) H/m
Plugging in the relevant values, we have;
B = (4π × 10^(-7) × 890 × 17000)/(2 × π × 0.7)
B = (2 × 10^(-7) × 890 × 17000)/(0.7)
B = 4.323 T
Answer:
1.635×10^-3m
Explanation:
Young modulus is the ratio of the tensile stress of a material to its tensile strain.
Young modulus = Tensile stress/tensile strain
Tensile stress = Force/Area
Given force = 130N
Area = Πr² = Π×(1.55×10^-3)²
Area = 4.87×10^-6m²
Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²
Tensile strain = extension/original length
Tensile strain = e/3.9
Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²
2×10¹¹N/m² = 8.39×10^7/{e/3.9)}
2×10¹¹ = (8.39×10^7×3.9)/e
2×10¹¹e = 3.27×10^8
e = 3.27×10^8/2×10¹¹
e = 1.635×10^-3m
The stretch of the steel wire will be
1.635×10^-3m
